Question

An electric fan is running on HIGH. After the LOW button is pressed, the angular speed of the fan decreases to 84.7 rad/s in 2.96 s. The magnitude of the angular deceleration is 47.2 rad/s2. Determine the initial angular speed of the fan.

Answer 1

The initial angular speed of the fan will be 55.0 rad/sec. The angular speed of the fan decreases to 84.7 rad/s in 2.96 s.

What is angular acceleration?

Angular acceleration is defined as the pace of change of angular velocity with reference to time.

Given data;

Final angular speed,$\rm \omega_f = 84.7 rad/s$

Initial angular speed, $\rm \omega_i = ?$

Time period,t= 2.96 s

Angular deceleration = 47.2 rad/s²

$\rm \alpha =\frac{\omega_f-\omega_i}{t} \\\\\rm 47.2 =\frac{84.7-\omega_i}{2.96} \\\\ \omega_i = 55.0 \ rad/sec$

Hence the initial angular speed of the fan will be 55.0 rad/sec.

To know more about angular acceleration refer to the link ;

brainly.com/question/408236

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