Question

you went to move a 41 kg bookcase to a different place in the living room. if you push with a force of 65 N and the bookcase accelerates at 0.12 m/s2 what is the coefficient of kinetic friction between the bookcase and the carpet?

Answer 1

Answer:

the force of friction = fk = (uk)n = 402(uk)

the net force acting to accelerate bookcase = ma = (41)(0.12) = 4.9 N

the {assumed horizontal} push force = 65 N

so

65 - fk = 4.9

fk = 65 - 4.9 = 60 N

uk = 60/402 = 0.15 <= ANS