you went to move a 41 kg bookcase to a different place in the living room. if you push with a force of 65 N and the bookcase acc
elerates at 0.12 m/s2 what is the coefficient of kinetic friction between the bookcase and the carpet?
1 answer:
Answer:
the force of friction = fk = (uk)n = 402(uk)
the net force acting to accelerate bookcase = ma = (41)(0.12) = 4.9 N
the {assumed horizontal} push force = 65 N
so
65 - fk = 4.9
fk = 65 - 4.9 = 60 N
uk = 60/402 = 0.15 <= ANS
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