Answer:
c. 2.6 h
Explanation:
The longest time spent over dinner is the time that you have available minus the minimum possible time spent in the trip.
The time of the trip is found using:
t =
Where distance is d and velocity is v. The time will be minimum at maximum velocity. Replacing with the data we have:
Ttrip = = 8.1818 h
Tdinner = 10.8h - 8.1818 h = 2.6181h
that aproximates 2.6 h.
Answer:
655128 ohm
Explanation:
C = Capacitance of the capacitor = 7.8 x 10⁻⁶ F
V₀ = Voltage of the battery = 9 Volts
V = Potential difference across the battery after time "t" = 4.20 Volts
t = time interval = 3.21 sec
T = Time constant
R = resistance
Potential difference across the battery after time "t" is given as
T = 5.11 sec
Time constant is given as
T = RC
5.11 = (7.8 x 10⁻⁶) R
R = 655128 ohm
Answer:
a) v = 0.0496 m / s , b) v = 0.0957 m / s
Explanation:
a) in this case we have an inelastic collision,
To solve these problems, the most important thing is to define the system formed by all the bodies, so that the forces during the crash have been internal and the amount of movement is conserved.
Therefore the system is made up of the ball and the player
initial instant. Before catching the ball
p₀ = m v₁
final moment. After you have grabbed the ball
= (m + M) v
the moment is preserved
po = p_{f}
m v₁ = (m + M) v
v = m / (m + M) v₁
let's calculate
v = 0.405 / (0.405 + 69) 8.50
v = 0.0496 m / s
in the same direction that the ball takes
b) In this case the ball bounces with a speed of V₂ = -7.80 m / s, the negative sign is because it is going in opposite directions
let's write the moment in two times
initial instant. Before the crash
p₀ = m v₁
try end. Right after the crash
p_{f} = m v₂ + M v
the moment is preserved
p₀ = p_{f}
m v₁ = m v₂ + M v
v = m (v₁ -v₂) / M
v = 0.405 /69 (8.50 - (7.80))
v = 0.0957 m / s
in the initial direction of the ball