Energy Density = 1/2 × ε(0) × (V/d)^2
V = 100, d = 0.01, ε(0) = 8.85 x 10^-12
Answer:
The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.
Explanation:
Distance refers to the length between any two points in space, while displacement refers to the distance from a start position to an end position regardless of the path.
In other words, distance refers to how much space an object travels during its movement; is the quantity moved. It is also said to be the sum of the distances traveled. The distance traveled by a mobile is the length of its trajectory and it is a scalar quantity. In this case, the distance is calculated as:
1850 m + 1200 m= 3,050 m
Displacement refers to the distance and direction of the final position from the initial position of an object. The displacement effected is a vector quantity. The vector representing the displacement has its origin in the initial position, its end in the final position, and its module is the distance in a straight line between the initial and final positions. That is, when expressing the displacement it is done in terms of the magnitude with its respective unit of measurement and the direction because the displacement is a vector type quantity. Mathematically, the displacement (Δd) is calculated as:
Δd= df - di
where df is the final position and di is the initial position of the object.
In this case, the displacement is calculated as:
1850 m - 1200 m= 650 m
Since the distance to the north is greater, the direction of travel will be to the north.
<u><em>The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.</em></u>
Answer:
gₓ = 23.1 m/s²
Explanation:
The weight of an object is on the surface of earth is given by the following formula:
where,
W = Weight of the object on surface of earth
m = mass of object
g = acceleration due to gravity on the surface of earth = strength of gravity on the surface of earth
Similarly, the weight of the object on Jupiter will be given as:
where,
Wₓ = Weight of the object on surface of Jupiter = 34.665 N
m = mass of object = 1.5 kg
gₓ = acceleration due to gravity on the surface of Jupiter = strength of gravity on the surface of Jupiter = ?
Therefore,
<u>gₓ = 23.1 m/s²</u>
Answer:
The box of rocks will have depression which can be seen without touching the box.
Explanation:
The density of rocks is very large as compared with napkins. So, the weight of the rocks will be much more greater than that of napkins.
As both boxes have same volume the heavier box will show depression on the lower surface as compared to the lighter box. So, the box of rocks will have depression which can be seen without touching the box.
<span>The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the "Radio waves"
So, option B is your answer
Hope this helps!
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