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diamong [38]
2 years ago
7

Which of these is a correct expansion of (3x − 1)(4x² + 5)?

Mathematics
1 answer:
My name is Ann [436]2 years ago
8 0
The correct expansion is B. 3x. 4x^2 + 3x•5 + (-1) • 4x^2+ (-1) • 5
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Evaluate P(5, 3). 15 20 60
insens350 [35]

Answer:

20.

Step-by-step explanation:

P(5,3)  = 5! / 3!

= (5*4*3*2*1) / (3*2*1)

= 20.

7 0
3 years ago
Omg!? Is 96 correct??
nlexa [21]
If you are finding the perimeter I believe you would just add up the four sides, getting 46
5 0
3 years ago
The number of oranges purchased varies directly as the price of the oranges. If 11 oranges cost $2.35, what is the cost of 18 or
lara31 [8.8K]

Answer:

If 11 oranges cost $2.35, then the cost of 18 oranges is $3.84.

Step-by-step explanation:

We have,

The number of oranges purchased varies directly as the price of the oranges.

If the cost of 11 oranges is $2.35.

It is required to find the cost of 18 oranges.

As their is direct relation between number and oranges and price.

So,

The cost of 1 orange is $\dfrac{2.35}{11}.

For finding the cost of 18 oranges, multiply 18 by $\dfrac{2.35}{11} such that,

C=18\times \dfrac{2.35}{11}\\\\C=3.84

So, If 11 oranges cost $2.35, then the cost of 18 oranges is $3.84.

4 0
3 years ago
Plss help me do this o-o
Vinvika [58]

Answer:

x=\sqrt6\\y=\sqrt{12}

Step-by-step explanation:

We know that since angles in a triangle add up to 180º, the remaining angle must be 45º.

So the side with length x must be equal to the side with length \sqrt6. That is:

x=\sqrt6

Now, by Pythagoras:

y=\sqrt{(\sqrt6)^2+(\sqrt6)^2}\\=\sqrt{6+6}\\=\sqrt{12}

4 0
2 years ago
Read 2 more answers
Help please with algebra problem
Strike441 [17]
Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243

Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400


Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
6 0
3 years ago
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