I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

Answer:
Step-by-step explanation:
5-2=3
other vehicles:Trucks::3:2
Without knowing the shape selection you have i cant really say anything. But with a square you wouldnt have any whole numbers, nor would a triangle give you whole number, than again no shape that i can think of would give whole numbers.
Answer:
21.2 or 15 sqrt of 2 (PETHAGOREOM theorem)
Step-by-step explanation:
a^2+b^2=c^2
20^2+5^2=C^2
400+25=C^2
450=C^2
sqrt 450=
15 sqrt of 2 or 21.2