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Vinvika [58]
2 years ago
13

At a diner, the lunch special gives you three choices. For the starter, you can pick from 3 choices (soup or salad or fries) For

the main item, you can pick from 2 choices (burger or sandwich) For the drink, you can pick from 2 choices (coke or pepsi) If the staff chooses all items for you randomly, figure these probabilities.
1. Probability of getting (soup, burger, coke)

2. Probability of getting (fries, burger, any drink)
Mathematics
1 answer:
MAXImum [283]2 years ago
6 0

Answer:

1/12; 1/6

Step-by-step explanation:

1. the chance of getting soup is 1/3, the chance of getting a burger is 1/2, and the chance of getting coke is 1/2, multiply these chances to get (1/3) *(1/2) * (1/2) = 1/12

2. the chance of getting fries is 1/3, the chance of getting a burger is 1/2, and the chance of getting any drink is 1, multiply these chances to get (1/3) * (1/2) * 1 = 1/6

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Rolling a Red and Yellow Dice
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Answer:

Option C 5/12 is correct option

Step-by-step explanation:

We have to find the probability that shows yellow dice has a larger value than the red dice.

Probability= total no of favorable outcomes / total no of outcomes

in our case, considering the data set, we have to find those pair where value of yellow die is greater than the red die. Where (1,2) represents 1 on the red die and 2 on the yellow die

(1,2) (1,3) (1,4) (1,5) (1,6)

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                                (5,6)

These are the possibilities where yellow die has greater value than red die.

total no of favorable outcomes = 15

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probability that yellow die has greater value than red die = 15 / 36

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Option C 5/12 is correct option

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