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Vinvika [58]
2 years ago
13

At a diner, the lunch special gives you three choices. For the starter, you can pick from 3 choices (soup or salad or fries) For

the main item, you can pick from 2 choices (burger or sandwich) For the drink, you can pick from 2 choices (coke or pepsi) If the staff chooses all items for you randomly, figure these probabilities.
1. Probability of getting (soup, burger, coke)

2. Probability of getting (fries, burger, any drink)
Mathematics
1 answer:
MAXImum [283]2 years ago
6 0

Answer:

1/12; 1/6

Step-by-step explanation:

1. the chance of getting soup is 1/3, the chance of getting a burger is 1/2, and the chance of getting coke is 1/2, multiply these chances to get (1/3) *(1/2) * (1/2) = 1/12

2. the chance of getting fries is 1/3, the chance of getting a burger is 1/2, and the chance of getting any drink is 1, multiply these chances to get (1/3) * (1/2) * 1 = 1/6

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Answer:

Step-by-step explanation:

1) ΔCPD & ΔEPF

∠CPD = ∠EPF   { Vertically opposite angles}

∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}

ΔCPD ≈ΔEPF  {AA criteria for similarity }

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Cross multiply

EF * 15 = 27 * 7.5

EF =\frac{27*7.5}{15}\\\\

EF = 27 * 0.5

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ii) EF // AB, so Triangles ACB & ECF are similar triangles

\frac{AB}{EF}=\frac{AC}{EC}\\\\\frac{22.5}{13.5}=\frac{AC}{22.5}

AC= \frac{22.5*22.5}{13.5}\\\\AC=37.5 cm

AC = 37.5 cm

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