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Vinil7 [7]
3 years ago
14

Plssss don't rude mee plsssplss help me in my testtt

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0
123344849&965588992929*weekusgdgendo
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Solve the following integral.<br><br> <img src="https://tex.z-dn.net/?f=%5Cint4x%5Ccos%282-3x%29dx" id="TexFormula1" title="\int
bagirrra123 [75]

Hi there!

\boxed{-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C}

To find the indefinite integral, we must integrate by parts.

Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":

u = 4x

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dv = cos(2 - 3x)

v = 1/3sin(2 - 3x)

Write into the format:

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Thus, utilize the solved for expressions above:

4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx

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-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx

Integrate the integral:

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-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C

Combine:

-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C

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3 years ago
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When a softball player gets a hit, it can be a single, double, triple, or home run. When Josephine is at bat, the probability th
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Find the sum of 2/3+(-1/3)
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2/3+(-1/3)
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