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weqwewe [10]
3 years ago
10

what is the actual length of the living space if the length of the scale drawing is 16.8 centimeters ? ​

Mathematics
1 answer:
Leto [7]3 years ago
8 0

Answer:

21 cm

Step-by-step explanation:

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Johnny Rockefeller had a bad credit rating and went to a local cash center. He took out a $100.00 loan payable in two weeks for
chubhunter [2.5K]

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156% interest annually so he payed 1/26 or 3.84615385%

Step-by-step explanation:

4 0
3 years ago
I need help solving ------> 2y = 18
Softa [21]

Answer:

y=4

Step-by-step explanation:

2y=8

after transposing

y=8/2

y= 4

4 0
3 years ago
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NO LINKS!! Please help me with this problem​
Vera_Pavlovna [14]

Information : The given hyperbola is a horizontal hylerbola with its centre (3 , -5) and one of its focus at (9 , -5) and vertex at (7 , -5) and as we can see that the focus and vertex have same y - coordinates, it must have its Transverse axis on line y = - 5.

Now,

it's vertex is given, I.e (7 , -5)

so, length of semi transverse axis will be equal to distance of vertex from centre, i.e

  • a = 7 - 3 = 4 units

Now, it's focus can be represented as ;

\qquad \sf  \dashrightarrow \: (3 + ae,  - 5 )

so,

  • ae + 3 = 9

and we know, a = 4

\qquad \sf  \dashrightarrow \: 4e + 3 = 9

\qquad \sf  \dashrightarrow \: 4e = 6

\qquad \sf  \dashrightarrow \: e =  \cfrac{3}{2}

Now, let's find the measure of semi - conjugate axis (b)

\qquad \sf  \dashrightarrow \:  {b}^{2}  =  {a}^{2} ( {e}^{2}  - 1)

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 16( \frac{9}{4}  - 1)

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 16( \frac{9 - 4}{4}  )

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 16( \frac{5}{4}  )

\qquad \sf  \dashrightarrow \:  {b}^{2}  = 20

\qquad \sf  \dashrightarrow \: b =   \sqrt{20}

So, it's time to write the equation of hyperbola, as we already have the values of a and b ~

\qquad \sf  \dashrightarrow \:  \cfrac{ {(x - h)}^{2} }{ {a}^{2} }  -  \cfrac{( {y  - k)}^{2} }{ {b}^{2} }  = 1

[ plug in the values, and h = x - coordinate of centre, and k = y - coordinate of centre ]

\qquad \sf  \dashrightarrow \:  \cfrac{ ({x-3)}^{2} }{ {16}^{} }  -  \dfrac{ {(y+5)}^{2} }{ { {20} }^{} }  = 1

6 0
2 years ago
Read 2 more answers
What is the meaning of the expression (4 + 5) x 2?
horsena [70]

Answer:

18.

Step-by-step explanation:

4+5 is 9, and 9 times 2 is 18

5 0
3 years ago
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Train completes journey of 150 miles one hour earlier if original speed is increased by 5mes/hour What is original speed
bija089 [108]
25mph.

using the equation distance = speed x time, you can make 2 equations. let x be the original speed of the train, and t be the original time it takes. the first equation is the original trip, the 2nd is your new speed and shortened time.
150=xt \\ 150=(x+5)(t-1)
this is because you are adding 5mph, and taking off 1 hour of time, to still cover the 150 miles. you can solve the first equation for t, and substitute into the second, and then solve for x.
t= \frac{150}{x}  \\ 150=(x+5)(t-1)=xt+5t-x-5 \\ 150=150+5( \frac{150}{x})-x-5 \\ 5= \frac{750}{x} -x \\ 5+x= \frac{750}{x}   \\ x^2+5x=750 \\ x^2+5x-750=0
and using the quadratic formula you can find x=25.
3 0
3 years ago
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