Answer:
It is important to use the regulatory sequence of a milk gene when constructing a recombinant gene used to produce a human protein secreted in milk because<em> it is capable of increasing or decreasing the expression of specific genes within an organism.</em>
Explanation:
<em>Regulatory Sequence</em> is<em> a segment of a nucleic acid molecule</em> which is capable of increasing or decreasing the expression of specific genes within an organism. Regulation of gene expression is an essential feature of all living organisms and viruses.
Answer:
Sub-threshold
Explanation:
If the stimulus is too small to generate the action potential, it is considered as subthreshold stimulus. Subthreshold stimulus causes the opening of small number of sodium channel i.e. not enough to generate action potential because action potential is generated by complete reversal of membrane polarity. Slight depolarization is caused by subthreshold stimulus by the opening of inadequate number of sodium channel but its magnitude is not enough to reach the threshold voltage. Consequently the action potential is not generated.
The response produced by subthreshold stimulus is called as local response or local depolarization because it could not travel further. The minimum stimulus required to generate the action potential is call as threshold stimulus and stimulus greater than threshold stimulus is called as suprathreshold stimulus. It changes the frequency of generated action potential.
<span>(3) parasite. Parasites are organisms that live on other organisms and cause harm to them.</span>
Answer:
Frequency of B allele is 0.6681
Explanation:
If p represents the frequency of dominant allele and q represents the frequency of recessive allele, according to Hardy-Weinberg equilibrium:
p + q = 1
p² + 2pq + q² = 1
where p² = frequency of homozygous dominant genotype
q² = frequency of homozygous recessive genotype
2pq = frequency of heterozygous genotype
Given that number of recessive chestnut horse = 28
Total horses = 226 + 28 = 254
frequency of b² genotype = 28/254 = 0.1102
frequency of recessive b allele = √0.1102 = 0.3319
So, frequency of B allele =
1 - 0.3319 = 0.6681
Hence frequency of B allele is 0.6681
