Complete Question:
A closed box has a square base with side length L feet and height h feet. Given that the volume of the box is 39 cubic feet, express the surface area of the box in terms of L only.
Answer:

Step-by-step explanation:
Given

Required
Express the surface area in terms of L
Because the box has a square base:
The volume is:

Where

So, we have:

Substitute 39 for Volume


Make H the subject

The surface area (A) of a box with square base is:


Open bracket

Substitute
for H




3x+50=6x-10
subtract 3x
50=3x-10
add 10
60=3x
divide by 3
20=x
Answer:
The interval of increase of g(x) is
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be
, the first derivative of the function is:


The following condition must be met to define the interval of increase:

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

The solution to this inequation is:

Now, the solution to this expression in interval notation is: 
J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6