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snow_tiger [21]
3 years ago
6

Help please!!

Mathematics
2 answers:
vitfil [10]3 years ago
6 0

Answer:

{ } or empty set

Step-by-step explanation:

zlopas [31]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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A closed box has a square base with side length feet and height feet. Given that the volume of the box is cubic feet, express th
Paha777 [63]

Complete Question:

A closed box has a square base with side length L feet and height h feet. Given that the volume of the box is 39 cubic feet, express the surface area of the box in terms of L only.

Answer:

A =  \frac{156}{L} + 2L^2

Step-by-step explanation:

Given

Volume = 39ft^3

Required

Express the surface area in terms of L

Because the box has a square base:

The volume is:

Volume = Base\ Area * Height

Where

Base\ Area = L * L

So, we have:

Volume = L * L * H

Substitute 39 for Volume

39= L * L * H

39= L^2 * H

Make H the subject

H = \frac{39}{L^2}

The surface area (A) of a box with square base is:

A = 2(LH + LH + L^2)

A = 2(2LH + L^2)

Open bracket

A = 4LH + 2L^2

Substitute \frac{39}{L^2} for H

A = 4L * \frac{39}{L^2} + 2L^2

A =  \frac{4L *39}{L^2} + 2L^2

A =  \frac{4*39}{L} + 2L^2

A =  \frac{156}{L} + 2L^2

4 0
3 years ago
PLEASE HELPP ILL GIVE BRAINLIEST
lesya [120]
The answer would be 75%
8 0
3 years ago
Read 2 more answers
What is the value of x?<br><br><br><br> Enter your answer in the box.
TiliK225 [7]
3x+50=6x-10
subtract 3x
50=3x-10
add 10
60=3x
divide by 3
20=x
6 0
3 years ago
Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.
galben [10]

Answer:

The interval of increase of g(x) is (-6,+\infty).

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be g(x) = 190 + 8 \cdot x^{3} + x^{4}, the first derivative of the function is:

g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}

g'(x) = 4 \cdot x^{2}\cdot (6+x)

The following condition must be met to define the interval of increase:

4\cdot x^{2} \cdot (x+6) > 0

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

x + 6 > 0

The solution to this inequation is:

x > - 6

Now, the solution to this expression in interval notation is: (-6,+\infty)

3 0
3 years ago
Points ), K and L are collinear with J between L and K. IF KJ = 28 - 3, LK = 9x + 7 and LJ = 4x - 8,
babymother [125]

J, K, and L are collinear

J is between K and L

LK = KJ + LJ

LK = 9x + 7

KJ = 2x - 3

LJ = 4x - 8

9x + 7 = (2x - 3) + (4x - 8)

9x + 7 = (2x + 4x) + (-3 - 8)

9x + 7 = 6x + -11

9x + 7 = 6x - 11

9x + 7 - 7 = 6x - 11 - 7

9x = 6x - 18

9x - 6x = 6x - 6x - 18

3x = -18

x = -6

∴ The value of x is -6

6 0
2 years ago
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