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snow_tiger [21]
3 years ago
6

Help please!!

Mathematics
2 answers:
vitfil [10]3 years ago
6 0

Answer:

{ } or empty set

Step-by-step explanation:

zlopas [31]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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Please answer these questions!!!!
Virty [35]

Answer:

BEC = C. 50

BCD = A. 120

Step-by-step explanation:

BEC

65 + 65 = 130

180 - 130 = 50

BCD = 180 - 60 = 120

BEC is 50

4 0
1 year ago
Read 2 more answers
Which of these equations have no solution? Check all that apply.
ollegr [7]

Answer:

the first one

Step-by-step explanation:

6 0
3 years ago
Read 3 more answers
ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
  (5/8 -1/6 -1/12)AB·h = 30 cm²
  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
6 0
3 years ago
Please help with the questions in the image
allochka39001 [22]

Answer:

fghjk

Step-by-step explanation:

6 0
3 years ago
Whats 0909090909090909090909090909+4
LiRa [457]

Answer:

0909090909090909090909090913

Step-by-step explanation:

brainliest plz

6 0
2 years ago
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