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2 years ago

What is 3^-2 in evaluate expression

Mathematics

1 answer:

My name is Ann [436]2 years ago

4 0

The evaluate expression of $3^{-2}$ is 1/9

<h3>What is exponents and powers?</h3>

Exponent refers to the number of times a number is used in a multiplication. Power can be defined as a number being multiplied by itself a specific number of times. Exponent is the number to which a number is raised so as to define its power as a whole expression.

Given: $3^{-2}$

Now evaluate this we have to use

$x^{-2}$ = 1/x²

So,

$3^{-2}$ =1/3²

$3^{-2}$ =1/9

Hence, the evaluate form is 1/9.

Learn more about exponents and power here:

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Let X be the temperature in at which a certain chemical reaction takes place, and let Y be the temperature in (so Y = 1.8X + 32)

Black_prince [1.1K]

Answer:

See explanation

Step-by-step explanation:

Solution:-

The random variable, Y be the temperature of chemical reaction in degree fahrenheit be a linear expression of a random variable X : The temperature in at which a certain chemical reaction takes place.

Y = 1.8*X + 32

- The median of the random variate "X" is given to be equal to "η". We can mathematically express it as:

P ( X ≤ η ) = 0.5

- Then the median of "Y" distribution can be expressed with the help of the relation given:

P ( Y ≤ 1.8*η + 32 )

- The left hand side of the inequality can be replaced by the linear relation:

P ( 1.8*X + 32 ≤ 1.8*η + 32 )

P ( 1.8*X ≤ 1.8*η ) ..... Cancel "1.8" on both sides.

P ( X ≤ η ) = 0.5 ...... Proven

Hence,

- Through conjecture we proved that: (1.8*η + 32) has to be the median of distribution "Y".

- Recall that the definition of proportion (p) of distribution that lie within the 90th percentile. It can be mathematically expressed as the probability of random variate "X" at 90th percentile :

P ( X ≤ p_.9 ) = 0.9 ..... 90th percentile

- Now use the conjecture given as a linear expression random variate "Y",

P ( Y ≤ 1.8*p_0.9 + 32 ) = P ( 1.8*X + 32 ≤ 1.8*p_0.9 + 32 )

= P ( 1.8*X ≤ 1.8*p_0.9 )

= P ( X ≤ p_0.9 )

= 0.9

- So from conjecture we saw that the 90th percentile of "X" distribution is also the 90th percentile of "Y" distribution.

- The more general relation between two random variate "Y" and "X" is given:

Y = aX + b

Where, a : is either a positive or negative constant.

- Denote, (np) as the 100th percentile of the X distribution, so the corresponding 100th percentile of the Y distribution would be : (a*np + b).

- When a is positive,

P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

= P ( a*X ≤ a*p_% )

= P ( X ≤ p_% )

= np_%

- When a is negative,

P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

= P ( a*X ≤ a*p_% )

= P ( X ≥ p_% )

= 1 - np_%

4 0

2 years ago

Mike and his dad are retiling his bathroom floor. They have budgeted $200 for the tiles and supplies. The tiles cost $1.85 each

Feliz [49]

Answer:

Equation: $114.90 + $1.85<em>x</em> = 200

Solution: They can buy 46 tiles.

Step-by-step explanation:

First, subtract 114.90 from both sides to get 1.85<em>x</em> = 85.10.

Divide 85.10 by 1.85 to get 46, which is the answer.

7 0

3 years ago

If f(x)=3x+1 and g(x)=x^2-6 find (f-g)(x)

8090 [49]

Hi there!

• f(x) = 3x + 1
• g(x) = x² - 6

Then,
According to th' question :-

(f - g)(x) = f(x) - g(x)

= 3x + 1 - (x² - 6)

= 3x + 1 - x² + 6

= -x² + 3x + 7

Hence,
Option 2ⁿᵈ : -x² + 3x + 7 is Correct.

~ Hope it helps!