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GarryVolchara [31]
4 years ago
5

How many distinguishable 7 letter​ "words" can be formed using the letters in alabamaalabama​?

Mathematics
1 answer:
otez555 [7]4 years ago
3 0
<span>You are given the word alabama and you are asked to find how many distinguishable 7 letter​ "words" can be formed from it.

ALABAMA has seven letters so we will start at 7! 
Counting the number of A's in the word we have 4 A's and so we will divide it by 4!
</span>Counting the number of L's in the word we have 1 L and so we will divide it by 1!
Counting the number of B's in the word we have 1 B and so we will divide it by 1!
Counting the number of M's in the word we have 1 M and so we will divide it by 1!

And so the number of ways is 7! / (4! x 1! x 1! x 1!) = 210 words.

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aleksandrvk [35]
He built 15 robots (4 + 8 + 3) = 15
he built an average of 5 robots per day....(4 + 8 + 3) / 3 = 15/3 = 5
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3 years ago
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The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
zimovet [89]

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

5 0
3 years ago
Gravity pulls the metal down at 10 N, but the metal pieces RISES! At least how much force is needed to make it move upward?
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Answer: Greater than 10 N

Step-by-step explanation:

Given

Gravity force on metal is 10 N

But the metal piece is rising i.e. there must be an upward force greater than 10 N

Suppose the force is F

So, we can write

\Rightarrow F>10\ N

Any force greater than 10 N is sufficient for the metal to move upwards

The greater the amount of force faster will be the movement

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Write two numbers that multiply to −33 and add to 8
cupoosta [38]

Answer:

-3 and 11

Step-by-step explanation:

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2 years ago
Evan, Claire, Jaya and Tim are running a 3km relay race.
Kruka [31]

Answer:

Tim needs to finish 59/90

Step-by-step explanation:

Add together what Evan Claire and Jaya ran  

9/10 + 7/9+ 2/3

The common denominator is 90

9/10 (9/9) +7/9 *10/10  + 2/3 *30/30

81/90 + 70/90 + 60/90

211/90

We need 3 km = 3 *90/90 = 270 /90

270/90 - 211/90 = 59/90

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