A=bh
1056=32<span>×b
</span>÷32 ÷32
3<span>3=h
The height is </span>3<span>3 inches.</span>
Answer:
slope = 7 or 7/1 <--- (7 over 1)
Step-by-step explanation:
rise = 7
run = 1
1/6 because you are breaking something into 6 and you got to share think of it like that so you get a smaller piece than you cutting it into 1/5...... so the answer is 1/6
The <span>given the piecewise function is :
</span>
![f(x) = \[ \begin{cases} 2x & x \ \textless \ 1 \\ 5 & x=1 \\ x^2 & x\ \textgreater \ 1 \end{cases} \]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5C%5B%20%5Cbegin%7Bcases%7D%20%0A%20%20%20%20%20%202x%20%26%20x%20%5C%20%5Ctextless%20%5C%20%201%20%5C%5C%0A%20%20%20%20%20%205%20%26%20x%3D1%20%5C%5C%0A%20%20%20%20%20%20x%5E2%20%26%20x%5C%20%5Ctextgreater%20%5C%201%20%0A%20%20%20%5Cend%7Bcases%7D%0A%5C%5D)
To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25
To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4
To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4
To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
================================
So, the statements which are true:<span>
![\framebox {B. f(2) = 4} \ \framebox {D. f(1) = 5}](https://tex.z-dn.net/?f=%5Cframebox%20%7BB.%20f%282%29%20%3D%204%7D%20%5C%20%5Cframebox%20%7BD.%20f%281%29%20%3D%205%7D)
</span><span>
</span>
W=2L-3
W*L=193
replace W with 2L-3: (2L-3)L=193
2L^2-3L-193=0
Cannot factor
are you sure the numbers are correct?
If it cannot be factored, use the quadratic formula to find out L, then you can find out W
use the Pythagorean theorem to find the diagonal. I don't see an easier way.