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Alla [95]
2 years ago
8

A manufacturer of skis produces 2 types: downhill and cross country. Times for manufacturing each ski are given

Mathematics
1 answer:
hjlf2 years ago
3 0

To maximize profit 14 downhill and 24 cross country should be produced.

<h3>How to find the intersecting point?</h3>

Let X represent the number of downhill skis and Y represent the number of cross country skis.

Manufacturing each ski: Downhill 3 hours Cross Country 2.5 hrs

Finishing time per ski: Downhill 0.5 hours Cross Country 0.5 hours

Total manufacturing time taken = (3)x+ (2.5+) y = 3x +2.5y ≤ 102

total finishing time taken = 0.5x+0.5 y ≤ 19

Profit function

Z = 80x + 90y

The objective is to maximize Z

By solving the two equations we get an intersecting point

(x,y) = (14,24)

In the feasible region corner points are (0, 36) (41,0)

So to maximize profit 14 downhill and 24 cross country should be produced.

Learn more about maximizing profit;

brainly.com/question/14642685

#SPJ1

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following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

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\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

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