I think you have to times your number you got by 2
There are several conditions where triangles can be proved similar:
AA - where two of the angles are same.
SAS - where two sides of a triangle compare to the corresponding sides in the other are in same proportion, and the angle in the middle are equal.
SSS - Where all sides in a triangle and the corresponding sides are in the same proportion.
In the case above, we can only use the method of SAS, as only two sides of the triangles are given.
<HMG = <JMK (vertically opposite angles)
HM/MK = 8/12 = 2/3
GM/MJ = 6/9 = 2/3
As the two sides of a triangle comparing to the corresponding sides in the other are in same proportion, and the angle in the middle are equal, the above triangles are similar, with the prove of SAS.
Therefore, the answer is C.yes by SAS.
Hope it helps!
It has to do with the unit circle, I think it is A because it should be 2(0+ (-1)) but I would probably wait for someone to come behind me and explain it better sorry couldn't help more
Answer:
idk what you asking but if it solve for for x it going be no solution
Your answer is x = 2.92 = 3.
To answer this question you need to use trigonometry, so the first step is to identify the hypotenuse, opposite, and adjacent.
Because the angle 73 is in the bottom corner next to the length x, we know that the length x is the adjacent. The length 10 is opposite the right angle so this must be the hypotenuse.
We know that cos(θ) = adjacent/hypotenuse, so we can substitute in what we know:
cos(θ) = adjacent/hypotenuse
cos(73) = x/10
Now we can rearrange for x:
cos(73) = x/10
× 10
cos(73) × 10 = x
Finally we just type this into the calculator and get the answer as 2.92 or 3.
I hope this helps!
