2 3

Mathematics

1 answer:

lyudmila [28]2 years ago

7 0

Answer:

the first answer option

Step-by-step explanation:

|x + 4| = 2

so,

(x + 4) must be +2 or -2 to make the original equation true.

when is (x + 4) = 2 ?

x + 4 = 2

x = -2

when is (x + 4) = -2 ?

x + 4 = -2

x = -6

so, -6 and -2 are the correct solutions.

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Question 11 (5 points)

KATRIN_1 [288]

Answer:

Yes

Step-by-step explanation:

Substitute the x value in the ordered pair for the x in the equation, or 2, and the y-value (6) in for y. So, 2 + 6 = 8, and this is true. Then do 3(2) - 6 = 0, which is also true.

6 0

3 years ago

Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park:

pashok25 [27]

That would be the letter B.

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3 years ago

Read 2 more answers

Simplify $\frac{1+\sqrt{2}}{2+\sqrt{3}}$. Your solution can be converted to the form $A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$, where

Zina [86]

Answer:

A+B+C+D = 13

Step-by-step explanation:

The given expression is:

$\dfrac{1+\sqrt{2}}{2+\sqrt{3}}$

We have to simply it and express it in the form of:

$A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$

Multiply and divide the given expression with $2-\sqrt 3$ :

$\dfrac{1+\sqrt{2}}{2+\sqrt{3}} \times \dfrac{2-\sqrt 3}{2-\sqrt 3}\\\Rightarrow \dfrac{(1+\sqrt{2}) \times (2-\sqrt 3)}{(2+\sqrt{3})\times (2-\sqrt 3)}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{2^2-(\sqrt{3})^2}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{4-3}\\\Rightarrow \dfrac{2(1+\sqrt2)-(\sqrt3+\sqrt6)}{1}\\\Rightarrow 2(1+\sqrt2)-(\sqrt3+\sqrt6)$