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Akimi4 [234]
2 years ago
12

Which rule describes the function in the graph below?

Mathematics
1 answer:
m_a_m_a [10]2 years ago
3 0

The function that models the graph is given as:f(x)=\left \{ {{-\frac{1}{3}x+\frac{4}{3}  \ \ -8 < x < 2} \atop {-x^2+6\ \ -2 < x < 0}} \atop {6\ \ 0 < x < 4}, \ \ x+2\ \  4 < x < 7 \right.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The equation shown in the graph represents a piecewise function. Hence:

From the line through the point (-8, 4) and (-2, 2), the equation is f(x) = -(1/3)x + 4/3

From the curve through the point (-2, 2) and (0, 6), the equation is f(x) = -x² + 6

From the line through the point (0, 6) and (4, 6), the equation is f(x) = -6

From the line through the point (4, 6) and (7, 9), the equation is f(x) = x + 2

The function that models the graph is given as:f(x)=\left \{ {{-\frac{1}{3}x+\frac{4}{3}  \ \ -8 < x < 2} \atop {-x^2+6\ \ -2 < x < 0}} \atop {6\ \ 0 < x < 4}, \ \ x+2\ \  4 < x < 7 \right.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Answer:

\displaystyle 1\frac{1}{3}

Step-by-step explanation:

[3, 1] and [0, −3]

\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{3 + 1}{0 + 3} = \frac{4}{3} = 1\frac{1}{3}

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a)

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Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
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Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

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2√72÷√8±√2<br><br> I Need help with this question fast
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