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Ksivusya [100]
2 years ago
10

"absmiddle" class="latex-formula">
make x the subject
Mathematics
1 answer:
Svetllana [295]2 years ago
6 0

~~~~~~~~y = 1- \sqrt{ 1- \dfrac 2x}\\\\\\\implies \sqrt{ 1- \dfrac 2x} = 1 - y\\\\\\\implies 1 - \dfrac 2x = (1 -y)^2~~~~~~~~~~~~~;[\text{Square on both sides}]\\\\\\\implies \dfrac 2x  = 1-(1-y)^2\\\\\\\implies \dfrac{1}{x} = \dfrac{1-(1-2y+y^2)}{2}\\\\\\\implies x = \dfrac{2}{1-1+2y-y^2}\\\\\\\implies x = \dfrac{2}{2y-y^2}\\\\\\\implies x = -\dfrac{2}{y(y-2)}~~~~~~~~~~~~~~~~~;[y\neq 0,~ y \neq 2]\\

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Un deposito de agua tiene forma de prisma rectangular con los lados de la base de 25 y 20 metros. Calcula la altura que pueda co
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Answer:

La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.

Step-by-step explanation:

Para calcular el volumen de un prisma rectangular, es necesario multiplicar sus 3 dimensiones: longitud*ancho*altura. El volumen se expresa en unidades cúbicas.

En este caso, se conoce la longitud y el ancho, cuyos valores son 25 y 20 metros. A su vez, se sabe que el depósito de agua debe contener 1000 m³. Entonces, siendo:

Volumen= longitud*ancho*altura

Y reemplazando los valores se obtiene:

1000 m³= 25 m* 20 m* altura

Resolviendo:

1000 m³= 500 m²* altura

altura=\frac{1000 m^{3} }{500 m^{2} }

altura= 2 m

<u><em>La altura del depósito para que pueda contener 1000 metros cúbicos de agua es 2 m.</em></u>

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