Answer:
Understand the question and solve it
Step-by-step explanation:
it should be 8
to find median you line up the numbers in order and divide by 2
Answer: the value of the car in 2019 is $5269
Step-by-step explanation:
It loses 12% of its value every year. This means that the value of the car is decaying exponentially. We would apply the formula for exponential decay which is expressed as
A = P(1 - r)^t
Where
A represents the value of the car after t years.
t represents the number of years.
P represents the initial value of the car.
r represents rate of decay.
From the information given,
P = $21500
r = 12% = 12/100 = 0.12
t = 2019 - 2008 = 11 years
Therefore
A = 21500(1 - 0.12)^11
A = 21500(0.88)^11
A = 5269
Considering the least common factor of 15 and 18, it is found that they will depart from the central station at the same time at 11 AM.
<h3>How to find the time it takes for periodic events to repeat at the same time?</h3>
To find the time that passes between the events happening at the same time, we need to find the least common multiple of the periods.
In this problem, the periods are of 15 and 18, hence their lcm is found as follows:
15 - 18|2
15 - 9|3
5 - 3|3
5 - 1|5
1 - 1
Hence:
lcm(15,18) = 2 x 3 x 3 x 5 = 90 minutes.
They will depart from the central station at the same time in 90 minutes from 9:30 AM, hence at 11 AM.
More can be learned about the least common factor at brainly.com/question/16314496
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Answer:
D
Step-by-step explanation:
Here, we want to get the equation of the line perpendicular to;
y = -3x + 2
From here, we can compare with the standard form of the equation of a straight line which is;
y = mx + c
From here m = -3
The slope is -3
Now, if two lines are perpendicular, the product of their slopes is -1
Thus;
-3 * m = -1
m = 1/3
So we want to select an equation out of the options that has a slope of 1/3
Let us take a look at the last option
x -3y = 3
3y = x-3
divide through by 3
y = x/3-1
So here the coefficient of x is 1/3 which is the slope of the perpendicular line that we are looking for and is our slope
