Answer:
According to the passage, we have the next equation:
where "K" is a proportional constant
Leaving at the end with the next equation:
Integrating the equation, we have:
where "C" is a constant
Then, we have the 2 conditions for the problem:
1) t=0 → r=10
Replacing in the equation, we have C = 10
2) t=5 → r=8
Replacing in the equation, we have K = -0.4
Finally, the time which the snowball will be completely melted will be when r = 0. So replacing in the equation
t = 25 minutes
Check the picture below, so it reaches the maximum height at the vertex, let's check where that is
![h(t)=64t-16t^2+0 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+64}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 64}{2(-16)}~~~~ ,~~~~ 0-\cfrac{ (64)^2}{4(-16)}\right)\implies \stackrel{maximum~height}{(2~~,~~\stackrel{\downarrow }{64})}](https://tex.z-dn.net/?f=h%28t%29%3D64t-16t%5E2%2B0%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bvertex%20of%20a%20vertical%20parabola%2C%20using%20coefficients%7D%20%5C%5C%5C%5C%20h%28t%29%3D%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B-16%7Dt%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B64%7Dt%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B%2B0%7D%20%5Cqquad%20%5Cqquad%20%5Cleft%28-%5Ccfrac%7B%20b%7D%7B2%20a%7D~~~~%20%2C~~~~%20c-%5Ccfrac%7B%20b%5E2%7D%7B4%20a%7D%5Cright%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28-%5Ccfrac%7B%2064%7D%7B2%28-16%29%7D~~~~%20%2C~~~~%200-%5Ccfrac%7B%20%2864%29%5E2%7D%7B4%28-16%29%7D%5Cright%29%5Cimplies%20%5Cstackrel%7Bmaximum~height%7D%7B%282~~%2C~~%5Cstackrel%7B%5Cdownarrow%20%7D%7B64%7D%29%7D)
Answer: (4,8) which is choice A
f = 2/3 is the scale factor
x = 6 and y = 12 pair up to get the coordinates for point K's location
multiply f by x and y to get the new location
f*x = (2/3)*6 = (2/3)*(6/1) = (2*6)/(3*1) = 12/3 = 4
f*y = (2/3)*12 = (2/3)*(12/1) = (2*12)/(3*1) = 24/3 = 8
The results we get are 4 and 8. So (6,12) moves to (4,8)
This scale factor 2/3 = 0.667 is less than 1, so the image is smaller compared to the pre-image.
Answer:
Step-by-step explanation:
-7/3, -2 5/8, -2.9
-2 1/3, -2 5/8, -2 9/10
-2 9/10, -2 5/8, -2 1/3
this is the order from least to greatest
-2.9, -2 5/8, -7/3
