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ahrayia [7]
3 years ago
9

Completing the square when the equation doesn't equal 0, e.g.

Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0
It's as it is said y = x^2+6x+12.
Your question is unclear.
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I have assessment quiz please
alekssr [168]

Answer:

A&B

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...

....

.......

.....

7 0
2 years ago
The coordinates of the endpoint of QS are Q(-9,8) and S(9,-4). Point R is on cue as such that QR:RS Is in the ratio 1:2. What ar
marishachu [46]

R(–3, 4)

Step-by-step explanation:

Let Q(-9,8) and S(9,-4) be the given points and let R(x, y) divides QS in the ratio 1:2.

By section formula,

R(x, y)=R\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=-9, y_{1}=8, \text { and } x_{2}=9, y_{2}=-4 \text { and } m=1, n=2

Substituting this in the section formula

R(x, y)=R\left(\frac{1(9)+2(-9)}{1+2}, \frac{1(-4)+2(8)}{1+2}\right)  

To simplifying the expression, we get

\Rightarrow R(x, y)=R\left(\frac{9-18}{3}, \frac{-4+16}{3}\right)

\Rightarrow R(x, y)=R\left(\frac{-9}{3}, \frac{12}{3}\right)

⇒ R(x,y) = R(–3,4)  

Hence, the coordinates of point R is (–3, 4).

6 0
3 years ago
(b) dy/dx = (x - y+ 1)^2
Elanso [62]

Substitute v(x)=x-y(x)+1, so that

\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}

Then the resulting ODE in v(x) is separable, with

1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx

On the left, we can split into partial fractions:

\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx

Integrating both sides gives

\dfrac{\ln|1-v|+\ln|1+v|}2=x+C

\dfrac12\ln|1-v^2|=x+C

1-v^2=e^{2x+C}

v=\pm\sqrt{1-Ce^{2x}}

Now solve for y(x):

x-y+1=\pm\sqrt{1-Ce^{2x}}

\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}

3 0
3 years ago
Explain the difference between prime and composite numbers
Fed [463]
Prime only has two factors one and its self a composite number has more factor than one and its self
exsample:     12 -  1,2,3,4,6,12  = 12 is a composite number
                       7  -  1,7                 =prime number 
4 0
3 years ago
Answer this: 15 cookies to 40 brownies as a ratio in simplest form.
Nutka1998 [239]
Solutions

⇒15 Cookie to 40 brownies can be written as 15:40

⇒15:40 is the ratio we have to simplify

The GCF of 15 and 40 is 5 so we divide them by 5 

15 ÷ 5 = 3
40 ÷ 5 = 8

3:8 is in simplest form



8 0
3 years ago
Read 2 more answers
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