A) around 13 ish. It's hard to frel the exact point. B) 26.08 C) .77 I hope that this helps
Answer:
The time a student learns mathematics is important for their score
Step-by-step explanation:
Observe the boxes diagrams. Where the horizontal axis represents the score obtained by the students in the test.
The vertical lines that divide the boxes in two represent the value of the median.
The median is the value that divides 50% of the data.
For the class of the morning the value of the median is 50 points, with a maximum value of 80 and a minimum value of 10.
For the afternoon class, the median value is 65 points with a minimum value of 30 and a maximum value of 100.
This indicates that in general, the highest number of high scores were obtained in the afternoon class.
Therefore it can be said that the time a student learns mathematics is important for their score
Answer:
2. 1 / a^2
3, 1
4. - 1
Step-by-step explanation:
Formulas : -
x^y / x^z = x^( y - z )
x^-y = 1 / x^y
x^y / x^y = 1
2.
a^2 / a^4
= a^( 2 - 4 )
= a^-2
= 1 / a^2
3.
m^6 / m^6 = 1
4.
- 8^4 / 8^4
= - 1 x 8^4 / 7^4
= - 1
Answer: With that assumption, we have a square, whose area is given by the formula Asquare=a2, and two semicircles. The distance D is simply the square's diagonal. The area of each semicircle is given by the formula Asemicircle=π*r2/2. then you will get your answer!
The system is:
i) <span>2x – 3y – 2z = 4
ii) </span><span>x + 3y + 2z = –7
</span>iii) <span>–4x – 4y – 2z = 10
the last equation can be simplified, by dividing by -2,
thus we have:
</span>i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
iii) 2x +2y +z = -5
The procedure to solve the system is as follows:
first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:
i) 2x – 3y – 2z = 4
iii) 2x +2y +z = -5
2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.
Equalize:
3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9
similarly, using i and ii, eliminate x:
i) 2x – 3y – 2z = 4
ii) x + 3y + 2z = –7
multiply the second equation by 2:
i) 2x – 3y – 2z = 4
ii) 2x + 6y + 4z = –14
thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:
3y+2z+4=-6y-4z-14
9y+6z=-18
So we get 2 equations with variables y and z:
a) 5y+3z=-9
b) 9y+6z=-18
now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.
Let's use elimination method, multiply the equation a by -2:
a) -10y-6z=18
b) 9y+6z=-18
------------------------ add the equations:
-10y+9y-6z+6z=18-18
-y=0
y=0,
thus :
9y+6z=-18
0+6z=-18
z=-3
Finally to find x, use any of the equations i, ii or iii:
<span>2x – 3y – 2z = 4
</span>
<span>2x – 3*0 – 2(-3) = 4
2x+6=4
2x=-2
x=-1
Solution: (x, y, z) = (-1, 0, -3 )
Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:
check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
