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ser-zykov [4K]
2 years ago
10

Solve the equation -8 = -3 - 6 cube root x^2

Mathematics
1 answer:
Volgvan2 years ago
5 0

Answer:

0.76

Step-by-step explanation:

-8+3=-6x^(2/3)

-5=-6 x^(2/3)

-5/-6=x^(2/3)

(2/3)√{5/6}=x

0.76=x

x=0.76

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nahhhh im goood. 6235736203274352

6 0
2 years ago
A circle is described by the equation x2 y2 14x 2y 14 = 0. what are the coordinates for the center of the circle and the length
bearhunter [10]

Answer:

length is (-7,-1) and radius is 6

Step-by-step explanation:

We are given the expression of the equation of a circle that is

x2 + y2 + 14x + 2y + 14 = 0.

Using completing the squares:

x2 + y2 + 14x + 2y + 14 = 0(x+7)^2 + (y+1) ^2 = -14 + 49 + 1(x+7)^2 + (y+1) ^2 = 36 center thus is at (-7,-1) and the radius is equal to square root of 36 equal to 6.

6 0
10 months ago
A train is traveling at a constant speed. The table shows the distance the train travels at different times during the trip. How
SpyIntel [72]
The train is traveling at 165 mph

495/3=165
825/5=165
1155/7=165
1485/9=165
8 0
3 years ago
A sample of 16 items from population 1 has a sample variance 5.8 and a sample of 21 items from population 2 has a sample varianc
Nady [450]

Answer:

Reject the null hypothesis.

Step-by-step explanation:

n1 = 16

n2 = 21

S.V1 = 5.8

S.V2 = 2.4

\alpha = 0.05

H_{0} = Population Variance 1 ≤  Population Variance 2

H_{a} = Population Variance 1 >  Population Variance 2

Test statistic value = 5.8 / 2.4 = 2.417

Degrees of freedom is n - 1

15 and 20

Critical value is F_{0.05} = 2.2

2.417 > 2.2

we reject the null hypothesis as the critical value is greater than the test statistic.

3 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
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