Light A flashes every 2 minutes while light B flashes every 7. The goal is to figure out when both lights flash at the same time and then figure out the other part later. You have to find the common multiples of 7 and 2. Meaning that you have to find out which number can they both be multiplied into. In this case, it is 14 because 7 can be multiplied by 2 to get 14 and 2 can be multiplied by 7. So if every 14 minutes they flash together at the same time, now you need to find out what time AFTER 3 will they both flash. You know that they both flashed at 1:00 so they will flash again at 1:14 and 1:28 and so on, but you need to find out when is the soonest they will flash after 3. 2 hours after the 1:00 flash will be 3:00 so that is 120 minutes. 120 minutes divided by 14 minutes comes to 8.5 but you dont need the decimal. Just simply multiply 14 by 8 and that comes to 112 minutes and if you add that to 1:00 you get 2:52. so they flashed at 2:52 so the next time they flash will be 14 minutes after 2:52. Sorry for the super long answer
Answer:
See explanation below
Step-by-step explanation:
BD - diagonal Added Construction
m∠CBD = m∠ADB Alternate Interior Angles Theorem
BD ≅ DB Reflexive Property
m∠A = m∠C Opposite ∠'s Congruent Theorem
ΔABD ≅ ΔCDB AAS or SAS
BC ≅ DA CPCTC
AC - diagonal Added Construction
m∠BCA = m∠CAD Alternate Interior Angles Theorem
AC ≅ CA Reflexive Property
m∠B = m∠D Opposite ∠'s Congruent Theorem
ΔABC ≅ ΔCDA AAS or SAS
AB ≅ CD CPCTC
Answer:
D. x<2
Step-by-step explanation:
-1+ 6-1-3x) >- 39 - 2x
Multiply the parentheses by 6
- 1-6 - 18x > - 39 - 2x
Calculate
7- 18x > - 39 - 2x
Move the terms
18x + 2x > -39 +7
Collect like terms Calculate
- 16x>-32
Divide both sides by - 16
x < 2
Answer:
l=0.1401P\\
w =0.2801P
where P = perimeter
Step-by-step explanation:
Given that a window is in the form of a rectangle surmounted by a semicircle.
Perimeter of window =2l+\pid/2+w
Or 
To allow maximum light we must have maximum area
Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle
Hence we get maximum area when i derivative is 0
i.e. 
Dimensions can be
Answer:
I Do
Step-by-step explanation:
