for 6
in a
given
slope(m)=1
point=(2,-4)=(x1,y1)
we know
equation of straight line
y-y1=m(x-x1)
y+4=1(x-2)
y+4=x-2
therefore x-y-6=0 is the required equation
substituting with ax+by+c=0 we get
a=1
b= -1
c= -6
Answer:
The area of the triangle is of 21 units of area.
Step-by-step explanation:
The area of a triangle with three vertices 
is given by the determinant of the following matrix:
In this question:
Vertices (3,0) (9,0) (7,6). So
The area of the triangle is of 21 units of area.
Assuming angle F is 68°, angle H will be
.. 360° -2*102° -68° = 88° . . . . . . . . selection B
Answer:
y = (1/3)x + 7
Step-by-step explanation:
The general structure form of a line in slope-intercept form is:
y = mx + b
In this form, "m" represents the slope and "b" represents the y-intercept.
The slope of a perpendicular line is the opposite-signed, reciprocal of the original line's slope. Therefore, if the slope of the original line is m = -3, the new slope is m = 1/3.
The y-intercept can be found by plugging the new slope and the values from the point (-3, 6) into the slope-intercept form equation.
m = 1/3
x = -3
y = 6
y = mx + b <----- Slope-intercept form
6 = (-3)(1/3) + b <----- Insert values
6 = -1 + b <----- Multiply -3 and 1/3
7 = b <----- Add 1 to both sides
Now, that you have the slope and y-intercept, you can construct the equation of the perpendicular line.
y = (1/3)x + 7
