All categories

1 year ago

What is the solution to the inequality lx-4l=3

Mathematics

1 answer:

xxMikexx [17]1 year ago

8 0

Answer: x = 7, x = 1

Step-by-step explanation:

|x-4| = 3

we know either x-4 = 3 or x-4 = -3

x-4 + 4 = 3 + 4

x = 7

x - 4 + 4 = -3 + 4

x = 1

You might be interested in

Write an algebraic expression for the perimeter of a rectangular garden with a width of 3 metres and a length of 2y metres. Simp

anyanavicka [17]

Answer:

P = 2(2y+3)

P = 30

Step-by-step explanation:

P = 2 (L+W) or P = L + L + W + W

P = 2 (2y+3)

P = 4y+6

Plug in 6 for y.

P = 24+6

P = 30

5 0

2 years ago

help asap im in a quiz, please show some sort of proof. and please dont say,¨ the answer is in the photo, and then send me a lin

Setler [38]

The answer would be D i think because if the two angles are to equal 72, and one of the angles equals 42, 72-42= 30. to find x, you’d do 30/6 which equals 5. so x=5 and the angle measure would be 30

4 0

3 years ago

Jose estimates that if he leaves his car parked outside his office all day on a weekday, the chance that he will get a parking t

Elan Coil [88]

Answer:

Therefore, the probability is P=0.74.

Step-by-step explanation:

We know that Jose estimates that if he leaves his car parked outside his office all day on a weekday, the chance that he will get a parking ticket is 26%.

Therefore the probability that he will get a parking ticket is P1=0.26.

We calculate the probability that he will not get a parking ticket.

We get:

P=1-P1

P=1-0.26

P=0.74

Therefore, the probability is P=0.74.

8 0

3 years ago

Express 84,42 as a percentage of 74,05 rounded off to a whole number

Leto [7]

0.84, 0.42, 75 AND 5

5 0

3 years ago

Waiting Line Models:Movies tonight is a typical video and dvd movie rental outlet for home-viewing customers. During the weeknig

pentagon [3]

Answer:

Probability [No customers in system] = 0.375
Customers waiting for service = 25/24
Average time customer wait = 1.25/1.5
May be wait
Per customer average time = 1.33 (Approx)

Step-by-step explanation:

Given:

Arrival rate λ = 1.25 min

Mean μ = 2

Computation:

(a) Probability [No customers in system]

Probability [No customers in system] = 1-[λ/μ]

Probability [No customers in system] = 1-[1.25/2]

Probability [No customers in system] = 0.375

(b) Customers waiting for service

Customers waiting for service = λ²/ [μ(μ-λ)]

Customers waiting for service = 1.25²/ [2(2-1.25)]

Customers waiting for service = 25/24

(c) Average time customer wait

Average time customer wait = λ / [μ(μ-λ)]

Average time customer wait = 1.25/ [2(2-1.25)]

Average time customer wait = 1.25/1.5

(d) May be wait because Customers waiting for service = 25/24

(e) Per customer average time

Per customer average time = 1/(μ-λ)

Per customer average time = 1/(2-1.25)

Per customer average time = 1.33 (Approx)

7 0

2 years ago