The answer is C.
hope this helps
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
Length = 10.5units,Area = 68.25 unit²
Step-by-step explanation:
Perimeter =34 units
Width =6.5 units
Perimeter = l+l+w+w
Where l= length and w= width
34 = l + l + 6.5+ 6.5
34.= 2l + 13
Subtract 13 from both sides
2l = 34 - 13
2l = 21
Divide both sides by 2
L= 21/2
Length = 10.5units
If we are to find the area.
Area = length x width
Area = 10.5 × 6.5
Area = 68.25 unit²
I hope this was helpful, please mark as brainliest
1 mm
Km etc
Hm etc
Dam etc
M 0.001
Dm 0.01
Cm 0.1
MM 1
Answer: the height of the prism is 14 cm.
Step-by-step explanation:
The formula for determining the volume of a rectangular prism is expressed as
Volume = length × height × width
Volume = LWH
The length of the prism is 3 times the width. It means that
L = 3W
The height is twice the width. This means that
H = 2W
Therefore,
Volume = 3W × × W × 2W = 6W³
The volume of a rectangular prism is 2,058 cubic cm. This means that
2058 = 6W³
Dividing through by 6, it becomes
343 = W³
W = 7
Therefore, the height of the prism would be
H = 2W = 2 × 7
H = 14 cm
