Ask question

Ask question

All categories

3 years ago

7

Kevin has a checking account. This month he deposits three paychecks. Each paycheck is for $225.75. He also makes two payments f

or utilities. Each payment is for $75. He makes a third payment for $125. What is Kevin's new account balance?

2 answers:

user100 [1]3 years ago

8 0

Answer:

402.25

Step-by-step explanation:

marin [14]3 years ago

4 0

402.5 (if this wrong then sorry)

You might be interested in

I need help with the attached

Aleksandr-060686 [28]

Answer: super sorry! i have no idea but im sure someone else knows (:

Step-by-step explanation:

sorry

8 0

2 years ago

What is the answer to 2/3 1/8 1/12?

Anna71 [15]

Your question seem to me non-understandable. Are they adding up together ?
or multiplying ?

5 0

3 years ago

(a) Find the first 3 terms in ascending powers of x of the binomial expansion of (2+x/2)^6

Firdavs [7]

Answer:(2+x/2)^6=64(1+3x/2+15x^2/16+5x^3/16+....) (2.05)^6=74.2203

Step-by-step explanation:

3 0

3 years ago

Solve the quadratic equation x2=25/36.<br><br><br>What are the solutions of the equation x2=25/36?

Alinara [238K]

Answer:

x is equal to positive 5/6 and negative 5/6

Step-by-step explanation:

To solve this, you simply need to take the square root of both sides:

$x^2 = \frac{25}{36}\\\sqrt{x^2} = \sqrt{\frac{25}{36}}\\x = \pm \frac{5}{6}$

7 0

3 years ago

Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u

soldier1979 [14.2K]

$x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }$

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

$p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}$

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

$\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}$

$\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}$

$\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}$

Therefore:

$\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]$

Recall that at t=25, $p(25)=\dfrac { 5800 } {13} \approx 446.15$

Therefore:

$\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009$

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0

3 years ago