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Kryger [21]
2 years ago
7

PLEASE HELPPPPP ME, IVE BEEN STUCK ON THIS ONE!!..

Mathematics
1 answer:
lianna [129]2 years ago
4 0

Answer:

<u>C. 9 minutes 30 seconds</u>

Step-by-step explanation:

well you could estimate it or just add 2.5 to 6.9 and you would get pretty close to the answer

<u>Have a good day! :)</u>

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A rectangle with vertices located at (1,2), (1,5), (3,5), and (3,2) is stretched horizontally by a factor of 3 with respect to t
Vika [28.1K]

Answer:

  18 square units

Step-by-step explanation:

The given rectangle has an x-dimension of 3-1 = 2, and a y-dimension of 5-2 = 3. Stretching the x-dimension by a factor of 3 will multiply it to ...

  2×3 = 6

and give you a rectangle 6 units wide by 3 units high. Its area will be ...

  (6 units)(3 units) = 18 units²

5 0
3 years ago
What is the converse of ​r-&gt;(~q v p)
alexira [117]

Answer:

 r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

Step-by-step explanation:

In general, remember that the converse of    a => b       is     \neg b  =>   \neg a , therefore in this case  a = r   \ \ ,  b = \neg q \ \lor p

so   r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

   

8 0
3 years ago
Find the perimeter of a rectangle with a length of 6x+3 and a width of -2x-5.
blsea [12.9K]
The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4

At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5

-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5

This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
8 0
3 years ago
Read 2 more answers
What is the solution to the system of equations? -2x + y = -5 3x – 2y = 12 A) (3, 1) B) (6, 3) C) (-2, -9) D) (-2, -1)
max2010maxim [7]

Answer:

The correct answer is D) (-2, -1)

Step-by-step explanation:

In order to solve this system of equations, start by multiplying the entire first equation by 2. Then add the two equations together. This will get the y's to cancel and allow you to solve for x.

-4x + 2y = -10

3x - 2y = 12

---------------------

-x = 2

x = -2

Now that we have the value for x, we can find y by plugging the x value into either equation.

-2x + y = -5

-2(2) + y = -5

-4 + y = -5

y = -1

6 0
3 years ago
-8y^10 / 2y^5<br> write using positive exponents
Rashid [163]

Answer:

Step-by-step explanation:

\dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\dfrac{-8y^{10}}{2y^{5}}=\dfrac{-4y^{10}}{y^{5}}=-4*y^{10-5}= -4y^{5}

3 0
3 years ago
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