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kap26 [50]
3 years ago
5

PLEASE HELP!!!! 20 POINTS!!!

Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0
Mass = density* volume
since density= mass/volume then mass/volume*volume=mass
= 4.5*0.4 =  1.80g

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Help pls- <br><br> I dont know it T^T
docker41 [41]

Answer:

Ans: H and A

Step-by-step explanation:

By the identity:

1-(cos(x))cos^{2}(x)+ sin^{2}(x)=1\\cos^{2}(x)=1- sin^{2}(x)\\\\cos(x)=\sqrt{1- sin^{2}(x)} \\sin(x)=\sqrt{1- cos^{2}(x)}\\\\\sqrt{1- cos^{2}(x)}/sinx=1\\\sqrt{1- sin^{2}(x)}/cosx=1\\\sqrt{1- cos^{2}(x)}/sinx+\sqrt{1- sin^{2}(x)}/cosx=2\\\\\\

Ans: H

For second quesiton, the transformation of a graph is that:

f(x) + k means vertical translation up by k units

Two curve have the same maximum value, so the graph doesn't translate upwards or downwards, thus b=0

Ans: A

7 0
3 years ago
If the line you graph is exactly the same as the first one, how many solutions do you
Aleks04 [339]
I think it’s infinitely many
5 0
3 years ago
The force, F (Newtons), between two objects is inversely proportional to the square of the distance, d (metres), between them.
snow_lady [41]

Answer:

d = 1.46 m

Step-by-step explanation:

We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:

From the question given above,

F is inversely proportional to square of d. This can be written as:

F ∝ 1/d²

F = K/d²

Cross multiply

K = Fd²

But:

Force (F) = 0.006 N

Distance (d) = 4 m

Constant (K) =?

K = Fd²

K = 0.006 × 4²

K = 0.006 × 16

K = 0.096 Nm²

Therefore, the relationship between the force (F) and the distance (d) is:

F = K/d²

F = 0.096 / d²

Finally, we shall determine the distance when the force is 0.045 N. This can be obtained as follow:

Force (F) = 0.045 N

Constant (K) = 0.096 Nm²

Distance (d) =?

F = K/d²

0.045 = 0.096 / d²

Cross multiply

0.045 × d² = 0.096

Divide both side by 0.045

d² = 0.096 / 0.045

Take the square root of both side.

d = √(0.096 / 0.045)

d = 1.46 m.

7 0
3 years ago
A semicircle is attached to the side of a rectangle as shown.
laiz [17]

Answer:

58.8\ mm^2

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of semicircle

step 1

Find the area of rectangle

The area of rectangle is equal to

A=bh

where

b=9\ mm\\h=3\ mm

substitute

A=(9)(3)=27\ mm^2

step 2

Find the area of semicircle

The area of semicircle is equal to

A=\frac{1}{2}\pi r^{2}

we have

r=9/2=4.5\ mm ---> the radius is half the diameter

\pi =3.14

substitute

A=\frac{1}{2}(3.14) (4.5)^{2}

A=31.8\ mm^2

step 3

Find the area of the figure

A=27+31.8=58.8\ mm^2

4 0
3 years ago
Read 2 more answers
The midpoint of AB is (-4,7) and point A is
levacccp [35]
Ok so, this one is a confusing one for me but what I recomend is going on a website call desmos , they have a graphing area there and use y=-4x-7 if I’m right, I do not know so don’t trust me on this
4 0
3 years ago
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