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1 year ago

What is the answer to this question

Mathematics

1 answer:

Lisa [10]1 year ago

4 0

Answer:8000 i think

Step-by-step explanation:

=20 to the power of nine-20 to the power of four=20 to the power of three.

20 to the power of three is 8000.

Hope this helps.

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The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou

Scilla [17]

Answer:

a) correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as $\sigma^2 = mean = 6.2$

hence, standard deviation is given as $\sqrt{6.2} = 2.48998$

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is

$P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)$

$= \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}$

= 0.002029 + 0.012582+ 0.039006

= 0.053617

= 0.0536

7 0

2 years ago

Karl is putting a frame around a rectangular photograph. The photograph is 14 inches long and 10 inches wide, and the frame is t

Sergeu [11.5K]

<h2>The area of the framed photograph = 1156 $inch^{2}$ </h2>

Step-by-step explanation:

Given,

The length of photograph (l) = 14 inches and

The breadth of photograph (b) = 10 inches

To find, the area of the framed photograph = ?

We know that,

The area of the framed photograph = (l + 2b)(l + 2b)

= (14 + 2 × 10) (14 + 2 × 10) $inch^{2}$

= (14 + 20) (14 + 20) $inch^{2}$

= (34) (34) $inch^{2}$

= 1156 $inch^{2}$

∴ The area of the framed photograph = 1156 $inch^{2}$

8 0

2 years ago

What is 6 1/10 plus 5 4/5 ASAP please

Virty [35]

Answer:

11 9/10

Step-by-step explanation:

6 + 5 = 11

1/10 + 4/5

1/10 + 8/10 = 9/10

11 + 9/10 = 11 9/10

HOPE THIS HELPS

PLZ MARK BRAINLIEST

5 0

2 years ago

Read 2 more answers

How do u do long division

Archy [21]

can you send me the actual problem so that i can solve it

8 0

2 years ago

On the way to work Juan carpools with a fellow co-worker then takes the city bus back home in the evening. The average speed of

podryga [215]

Answer:

$\frac{40r+100}{r(r+5)}$

Step-by-step explanation:

Let r represent speed in the carpool.

We have been given that on the way to work Juan carpools with a fellow co-worker then takes the city bus back home in the evening. The average speed of the 20-mile trip is 5 miles per hour faster in the carpool.

We know that time is equal to distance over speed.

The total distance is 20 mile. Time taken to travel 20 miles using carpool would be $\frac{20}{r}$

The speed on the bus is 5 miles greater, so it will be $x+5$ . Time taken to travel 20 miles using bus would be $\frac{20}{r+5}$

Total time will be equal to sum of both times that is:

$\frac{20}{r+5}+\frac{20}{r}$

Let us simplify our expression.

$\frac{20r}{r(r+5)}+\frac{20(r+5)}{r(r+5)}$

$\frac{20r}{r(r+5)}+\frac{20r+100}{r(r+5)}$

Combine numerator:

$\frac{20r+20r+100}{r(r+5)}$

$\frac{40r+100}{r(r+5)}$

Therefore, our required expression would be $\frac{40r+100}{r(r+5)}$ .

7 0

2 years ago