Step by step
One sixth of the sum 1/6 ( + )
the sum of d and 3 1/6 (d+3)
minus the product 1/6 (d+3) - ( )( )
The product of 4 and q 1/6 (d+3) - 4q
The product of p and 3 3p
is subtracted from - 3p
three-fourths of s 3/4 s - 3p
three-fourths the sum 3/4 ( + )
the sum of 9 and k 3/4 (9+k)
Obviously, the final line in each case is the answer.
I'm pretty sure it's y=4x-7. I could be wrong but the way I set it up is definitely close if not correct
Answer:
-21 = 6t
Step-by-step explanation:
3t - 7 = 5t
Subtract 3t from each side
3t-7-3t = 5t-3t
-7 = 2t
Multiply each side by 3 to get 6t
-7*3 = 2t*3
-21 = 6t
Using conversions between odds and probabilities, we have that:
1. A) 4:21
2. 0.952 probability that a bag of flour passes inspection.
3. C) 1:39
4. 41:59.
5. 14:11
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is given by a:b, in which <u>a is the number of successes and b is the number of failures</u>.
Item 1:
- Probability of 0.16, thus, for 100 trials, <u>16 successes and 84 failures</u>, and the odd is:
16:84, which, simplifying by 4, is 4:21.
Item 2:
- Odd of 20:1 means that 20 + 1 = <u>21 trials, there are 20 successes</u>, thus, the probability is:

0.952 probability that a bag of flour passes inspection.
Item 3:
- Probability of 0.025, thus, for 100 trials, <u>2.5 successes and 97.5 failures</u>, and the odd is:
2.5:97.5, which, simplifying by 2.5, is 1:39.
Item 4:
- 59% probability that he will take the longest trail, thus 100 - 59 = 41% probability of him <u>not tanking the longest trail</u>, thus, the odds against him taking the longest trail is 41:59.
Item 5:
- Probability of 0.56, thus, for 100 trials, <u>56 successes and 44 failures</u>, and the odd is:
56:44, which, simplifying by 4, is 14:11.
A similar problem is given at brainly.com/question/21094006