Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
46.9
Step-by-step explanation:
328/7 = 46.9
To double check: 46.9 x 7 = 328
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Answer:
x = 14 D
Step-by-step explanation:
(18x + 36) / 3 = 6x + 12
6x + 12 = -16 + 8x
-6x . -6x
12 = -16 + 2x
+16 . +16
28 = 2x
/2 . /2
14 = x
Change everything into 10ths as follows:
1/10 + 2.5/10 = 3.5/10 of an hour to make one bracelet. Then change to 20ths so the numerator is a whole number.
Divide your time available by the time it takes to make one.
21
4 = 420= 15 bracelets
7 28
20
(as a whole number there was no fraction or remainder to round off)
Answer:
at 6pm it was 18 degrees
Step-by-step explanation:
10 pm: -10
9 pm : -3
8 pm: 4
7 pm: 11
6 pm: 18
Add 7