(a) P( fifth one is bad) = P( first 4 are OK) * P(5th is bad)
= (0.98)^4 * 0.02 = 0.0184 or 1.84%
(b) this will be (0.98)^10 = 81.70%
Given:250 sheep in a 40-acre pasture.Number of sheep grazing in each acre.
250/40 = 6.25 or 6 sheep per acre
n = 6sample proportion: signified by ρSample 1: 4 → 4/6 = 0.67Sample 2: 1 → 1/6 = 0.17Sample 3: 9 → 9/6 = 1.50
multiply the sample proportion by 1-ρSample 1: 0.67(1-0.67) = 0.67(0.33) = 0.2211Sample 2: 0.17(1-0.17) = 0.17(0.83) = 0.1411Sample 3: 1.50(1-1.5) = 1.5(-0.5) = -0.75
divide the result by n. n = 6Sample 1: 0.2211/6 = 0.03685Sample 2: 0.1411/6 = 0.02352Sample 3: -0.75/6 = -0.125
square root of the quotient to get the standard error.Sample 1: √0.03685 = 0.1919Sample 2: √0.02352 = 0.1534Sample 3: √-0.125 = invalid
z value 95% confidence 1.96.
Sample 1: 1.96 * 0.1919 = 0.3761 or 37.61% margin of errorSample 2: 1.96 * 0.1534 = 0.3007 or 30.07% margin of error
16=2/3 times number of students
times both sides by 3
48=2 times number of students
divide both sides by 2
24=number of students
there aer 24 students i the club
I hope it’s correct
The answer:
5-4v=19
<em>C</em>
Approximately 95% of data falls within 2 standard deviations (±2) of the mean.
<em>Explanation</em>
According to the empirical rule of normal distribution:
Approximately 68% of the data falls within ±1 standard deviation of the mean
2. Approximately 95% of the data falls within ±2 standard deviations of the mean
3. Approximately 99.7% of the data falls within ±3 standard deviations of the mean.
Therefore, among the given options, only option C adheres to the empirical rule of the normal distribution. Therefore, the option C is correct
