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koban [17]
3 years ago
15

The temperature of a freezer is never greater than -2 Celsius. Yesterday the temperature was at -10 Celsius, but it increased at

a steady rate of 1.5 Celsius per hour. How long in hours and minutes did the temperature increase inside the freezer?
Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

13.5

Step-by-step explanation:

First I thought of all the answers,10, 2 and 1.5.

The added them all together.

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Has moved 30 minutes

4 0
3 years ago
Mr. Johnston spends 2/3 of every year in Florida how many months does he spend in Florida each year
musickatia [10]

Answer:

8 months

Step-by-step explanation:

12/3 = 4, 1/3 is 4 so 1/3 + 1/3 = 2/3 or 8

6 0
2 years ago
Can you please help me with solving this math problem. 1/4 (x+2)=5/6
Verdich [7]

So firstly, multiply both sides by 4 (the reciprocal of 1/4): x+2=\frac{20}{6}=3\frac{2}{6}

Next, subtract both sides by 2 and your answer will be: x=1\frac{2}{6}

6 0
3 years ago
Read 2 more answers
Fill in the arrows with the correct answer for each problem. Remember, begin at the START button highlighted in yellow.
Aliun [14]

Answer:

first 2.70, 4.00 , 7.20 , 7.65 , 6.00 , 12.60 , 62.50 , 45.00 ,32,00 , 12.60  and 2.00 done

Step-by-step explanation:

all correct

4 0
3 years ago
Read 2 more answers
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
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