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koban [17]
3 years ago
15

The temperature of a freezer is never greater than -2 Celsius. Yesterday the temperature was at -10 Celsius, but it increased at

a steady rate of 1.5 Celsius per hour. How long in hours and minutes did the temperature increase inside the freezer?
Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

13.5

Step-by-step explanation:

First I thought of all the answers,10, 2 and 1.5.

The added them all together.

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Answer:

|T- 98.6| \geq 3

And in order to solve this we have two possibilities:

Solution 1

T -98.6 \leq -3

And solving for T we got:

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Solution 2

And the other options would be:

T -98.6 \geq 3

T \geq 101.6

Step-by-step explanation:

For this case we can define the variable os interest T as the real temperature and we know that if we are 3 F more than the value of 98.6 we will be unhealthy so we can set up the following equation:

|T- 98.6| \geq 3

And in order to solve this we have two possibilities:

Solution 1

T -98.6 \leq -3

And solving for T we got:

T \leq 98.6- 3

T\leq 95.6

Solution 2

And the other options would be:

T -98.6 \geq 3

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6 0
3 years ago
ANSWER PLEASE *50 POINTS*
zvonat [6]

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Write a real world problem for: 80-3x=53
Oxana [17]

Answer:

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Step-by-step explanation:

In this real-world problem, the money he had at the beginning resembles the 80 in the equation. The -3x is the money he gives out to each of his friends. The 53 on the right-hand side is the money he has left after he gives the money away.

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Answer:

x = 1 +  \sqrt{5} x = 1 -  \sqrt{5}

7 0
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