Answer:
Step-by-step explanation:
You would never buy a 10-pack, because two 5-packs cost less.
To buy 3 bars you need a single bar and a pair of single bars for £0.82 + £0.82+ £0.41 = £2.05
To buy 30 bars you need 3 pairs of 5-bar packs = 3×£5.75 = £17.25
To buy the remaining 5 bars you need one 5-bar pack = £3
cost = £2.05 + £17.25 + £3 = £22.30
Answer:
Terms
Explanation:
Any expression is formed of terms separated by addition or subtraction.
A term can be a number, a variable or the product of multiplying a number and a variable.
Now, the given expression is:
a + 2b + 12c^2
This expression has three terms all separated by addition. These terms are:
a : which is only a variable
2b : which is the product of a number and a variable
12c^2 : which is the product of a number and a variable
Hope this helps :)
Answer:
10 bags for $5.49
Step-by-step explanation:
4 bags for $2.39 = 1 bag for $0.5975
10 bags for $5.49 = 1 bag for $0.549
Answer:
$14.77
Step-by-step explanation:
The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.
To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

By definition of absolute value,

Over this particular integration interval,
• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and
• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5
so you end up splitting the integral at <em>t</em> = <em>π</em> as

Now compute the distance:



making B the correct answer.