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Anna71 [15]
3 years ago
14

Help pls im confused

Mathematics
2 answers:
pochemuha3 years ago
4 0

it's the only one that hasn't been with a positive 2

svetoff [14.1K]3 years ago
4 0

Answer:

X = 3

Step-by-step explanation:

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the total weight of the medals won by the top medal-winning nations in the 2012 London Olympic Games.
V125BC [204]
22222222222222222222222222222222222222222222222222222222223333333333333333333333333333,221
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John recieved a notice that his bank account was overdrawn by $40. He made a deposit and now his balance is $25. How much did Jo
Vitek1552 [10]
He had to put $65 bc. he had to balance his account then added $25
8 0
3 years ago
Read 2 more answers
Fourteen seniors were asked how many minutes they spent on doing their homework the previous night. The data is displayed below.
Nadusha1986 [10]

Answer:

b

Step-by-step explanation:

We need to find the median of:-

73 75 87 65 69 62 81 64 68 101 74 71 89 87

First, we need to arrange the numbers in ascending order as below:-

62, 64, 65, 68, 69, 71, 73, 74, 75, 81, 87, 87, 89, 101

Since there are a total of 14 numbers, let's split it up into two halves (each of seven numbers)

62, 64, 65, 68, 69, 71, 73           |||             74, 75, 81, 87, 87, 89, 101

The median would be the mean of the two middle numbers i.e. the mean of 73 and 74

Median = \frac{73+74}{2}

= \frac{147}{2}

= 73.5

So, about half of the students spent less than 73.5 minutes doing homework and about half spent more than 73.5 minutes on homework

7 0
3 years ago
Read 2 more answers
Given f(x) = (lnx)^3 find the line tangent to f at x = 3
kirill [66]
Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

6 0
1 year ago
(x^3)^9 = <br> A: x^12 <br> B: x^27 <br> C: x^3 <br> D: x^6
Grace [21]
(x^3)^9=x^{27}
3 0
4 years ago
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