How many solutions does the system have

Mathematics

2 answers:

Delicious77 [7]3 years ago

4 0

Answer:

There are infinate solutions.

Step-by-step explanation:

Plug (3x-8) in for y

5(3x-8)=15x-40

Simplify

15x-40=15x-40

zimovet [89]3 years ago

4 0

<h3>Answer: Infinitely many solutions</h3>

Explanation:

If we multiply both sides of the second equation by 5, then we go from y = 3x-8 to 5y = 15x-40. This is exactly identical to the first equation of the system.

Therefore, the two equations are equivalent just in slightly different forms. The two equations graph the same line which leads to infinitely many solutions.

The solutions are of the form (x, 3x-8) where x is any real number.

Since there are infinitely many solutions, we consider this system to be dependent.

You might be interested in

How do you factor a quadratic equation completely?

oee [108]

Answer:

A Method For Simple Cases

Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.

Step 2: Rewrite the middle with those numbers:

Step 3: Factor the first two and last two terms separately:

Step-by-step explanation:

4 0