<h2>
Answer</h2>
After the dilation
around the center of dilation (2, -2), our triangle will have coordinates:



<h2>Explanation</h2>
First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:
→
Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor
. Therefore our second partial rule will be:
→
→
Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)
→
→
Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:













Now we can finally draw our triangle:
Answer:
3
Explanation:
3^2 is equal to 9, and 4^2 is equal to 16, so sqrt(10) must be in between 9 and 16. Since 10 is closer to 9 than to 16, sqrt(10) is closer to 3 than 4, which means that to the nearest integer sqrt(10)=3
Answer:
4 x 4 is 12
3 x 2 is 6
12 plus 6 is 18
Answer is 18
Step-by-step explanation:
Assume the parabola is placed on a graph where the x-axis is the top of the dish.
The vertex is then at (0,-30) The x-intercepts or zeros are at (-30,0) and (30,0)
The equation of such parabola would be:

Plug in vertex to find value of 'a'

Now find the focus given that


Answer: the microphone should be placed 7.5 inches from vertex.
8c + 6-3c -2
8c -3c + 6-2 = 5c + 4
Brainliest please!