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baherus [9]
2 years ago
10

Write the equation in slope-intercept form for the line with the given slope that contains the given point.

Mathematics
1 answer:
Roman55 [17]2 years ago
8 0

Answer:

D) y = 1x + 2

Step-by-step explanation:

The general structure of an equation in slope-intercept form is:

y = mx + b

In this equation, "m" stands for the slope and "b" stands for the y-intercept. You can substitute the given value of the slope into the equation. Since you are not given "b", you can plug the value of the points into the half-completed equation (with the slope) and isolate "b".

slope = m = 1

y = (1)x + b

(3,5) ------> y = 5 and x = 3

5 = 1(3) + b

5 = 3 + b

2 = b

Final Equation:

y = 1x + 2

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In the year 2017, an estimated 4,347,000 people in this country are illiterate.
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The number of people of the country which is predicted will be illiterate in the year 2025 are 1,300,700.

<h3>What is percentage decrease?</h3>

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In the year 2017, an estimated 4,347,000 people in this country are illiterate. With new incentives and funding, The country is hoping to cut that number by 14% every year.

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A) Let X be a random variable that can assume only positive integer values, and assume its probability function is P(X -n) A/3^n
kramer

Answer:

a) The value of A = 2

b) The value of B  = \dfrac{1}{12}

Step-by-step explanation:

a)

Given that:

X should be the random variable that assumes only positive integer values.

The probability function; P[X = n] = \dfrac{A}{3^n} for some constant A and n ≥ 1.

Then, let \sum \limits ^{\infty}_{n =1} P[X =n] = 1

This implies that:

A \sum \limits ^{\infty}_{n =1} \dfrac{1}{3^n}= 1

A \times  \dfrac{\dfrac{1}{3}}{1 - \dfrac{1}{3}} = 1

A \times  \dfrac{\dfrac{1}{3}}{\dfrac{2}{3}} = 1

A \times \dfrac{1}{2}=1

A = 2

Thus, the value of A = 2

b)

Suppose X represents a e constant A (n> 1). Find A.

b) Let X be a continuous random variable that can assume values between 0 and 3

Then, the density function of x is:

f_x(x) = \left \{ {{B(x^2+1)}   \ \ \ 0 \le x \le 3  \ \ \ \atop {0} \ \ \ otherwise} \right.

where; B is constant.

Then, using the property of the probability density function:

\int ^3_0 \ B (x^2+1 ) \ dx = 1\\

Taking the integral, we have:

B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1

B \Big [\dfrac{3^3}{3} +3 \Big ]= 1

B \Big [\dfrac{27}{3} +3 \Big ] = 1

B [ 9 +3 ] = 1

B [ 12 ] = 1

Divide both sides by 12

B  = \dfrac{1}{12}

5 0
3 years ago
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