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harkovskaia [24]
3 years ago
10

• Its ones digit is one more than its tens digit.

Mathematics
1 answer:
lesya [120]3 years ago
6 0

Answer:

is it 32

Step-by-step explanation:

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Ian walks down a sloped path. After 6 minutes, he is 3 m above street level. Write the equation in slope-intercept form of the l
Georgia [21]

Answer:

y=-2/3x+7

Step-by-step explanation:

Since you know the path is parallel to the equation y+-2/3x+12, you already know the slope is -2/3.

It says y is the height above street level, so that is 3. The problem says x is time, which is 6, so all you have to solve for is the y intercept.

3 (y, or the height above street level) = (-2/3) 6 (x, or time) + b (unknown y intercept)

3 = -4 + b

7 = b

So, y = -2/3x + 7

8 0
3 years ago
Read 2 more answers
Simplify each expression by writing the expression without absolute value bars
AysviL [449]

Answer:

-1

Step-by-step explanation:

When b<4

|b-4|  is negative

|b-4|  = - ( b-4)

- (b-4) / ( b-4) =

Factoring out (b-4)

-1

8 0
3 years ago
Factor completely h^3+2h^2-9h-18
guapka [62]

Step 1: Group this into two groups:

    h^3 + 2h^2-9h-18=(h^3 + 2h^2)+(-9h-18)

When you  do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.

Step 2: Factor out the GCF from both individual groups:

    (h^3 + 2h^2)+(-9h-18) = h^2 (h+2) -9(h+2)

Step 3: Notice both groups have that (h+2)?  That's a new GCF between the two groups, so factor that out:

    h^2 (h+2) -9(h+2) = (h+2)(h^2-9)

Step 4: That (h^2-9) piece can be factored further, since it's a difference of squares:

    (h+2)(h^2-9) = (h+2)(h+3)(h-3)

Now it's factored.

8 0
2 years ago
In 1983, a pair of jeans cost $66.35. If a pair of jeans costs $118.10 today, what is the CPI?
Alex73 [517]
Answer choice C
118.10/66.35=1.779 or 1.78
1.78x100=178
3 0
3 years ago
Read 2 more answers
the vertex of the parabola represented by f(x)=x^2-2x+6 has coordinates (1,5). Find the coordinates of the vertex of the parabol
Sever21 [200]
Plug \ in \ x+3 \ into \ f(x) \ to \ get \ g(x)&#10;\\\ g(x) = (x+3)^2-2(x+3)+6&#10;\\\ g(x)= x^2+6x+9 -2x-6+6&#10;\\\ g(x) = x^2+4x+9&#10;\\\ -\frac{b}{2a} --\ \textgreater \  vertex&#10;\\\ \frac {-4}{2}&#10;\\\ x \ coordinate = -2, plug \ it \ back \ into \ g(x)&#10;\\\ (-2)^2+4(-2)+9&#10;\\\ 4-8 + 9&#10;\\\ y \ coordinate = 5&#10;\\\ \boxed{(-2,5)}
5 0
3 years ago
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