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Mice21 [21]
2 years ago
14

Which points do the graph of f and g have in g(x)=log2x and g(x)=log10x

Mathematics
1 answer:
Pie2 years ago
7 0

Logarithmic are inverse of exponential functions. The point where graph of f and g intersect is (0, ∞)

<h3>Logarithmic function</h3>

Logarithmic are inverse of exponential functions. Given the following functions;

g(x)=log2x and g(x)=log10x

The point where the graphs intersect is the point where g(x) = g(x)

Equate

log2x = log10x

2x = 10x

The value of x that made them equal is 0

Determine the value of g(x)

g(0) = log2(0)

g(0) = ∞

Hence the point where graph of f and g intersect is (0, ∞)

learn more on log function here: brainly.com/question/13473114

#SPJ1

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<u>Answer:</u>

Equation t = 5c + 6d represents total cost t of c large pizzas and d large one-topping pizzas

<u>Solution:</u>

Given that

Cost of large pizza = $5 each

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Need to write the equation that represents total cost t of c large pizzas and d large one topping pizzas.

From given information

Cost of 1 large pizza = 5

So cost of c large pizzas   = c x 5 = 5c

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So cost of d large one-topping pizzas   =d x 6 = 6d

<em>Total cost t = cost of c large pizzas + cost of d large one-topping pizzas    </em>

=> t = 5c + 6d

Hence equation t = 5c + 6d  represents total cost t of c large pizzas and d large one-topping pizzas.    

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plan 1

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Find the value of x (4x-10) (x)
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3 years ago
PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
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Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

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4 years ago
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