Ángel and Jayden we’re at track practice.
The track is 2/5 kilometers around.
* Ángel ran 1 lap in 2 minutes.
* Jayden ran 3 laps in 5 minutes.
How far does Jayden run in one minute?
4 1/6 km
<span>radius=1/2 diameter
are=radius^2*3.14
Hope I helped, and good luck!</span>
Answer:
i really really like ya cut g
Step-by-step explanation:
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.
Answer: The correct option is B) about 34%
Proof:
We have to find ![P(4.2](https://tex.z-dn.net/?f=%20P%284.2%3Cx%3C5.1%29%20)
To find
, we need to use z score formula:
When x = 4.2, we have:
![z = \frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%20)
![=\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1](https://tex.z-dn.net/?f=%20%3D%5Cfrac%7B4.2-5.1%7D%7B0.9%7D%3D%5Cfrac%7B-0.9%7D%7B0.9%7D%3D-1%20)
When x = 5.1, we have:
![z = \frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=%20z%20%3D%20%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%20)
![=\frac{5.1-5.1}{0.9}=0](https://tex.z-dn.net/?f=%20%3D%5Cfrac%7B5.1-5.1%7D%7B0.9%7D%3D0%20)
Therefore, we have to find ![P(-1](https://tex.z-dn.net/?f=%20P%28-1%3Cz%3C0%29%20)
Using the standard normal table, we have:
= ![P(z](https://tex.z-dn.net/?f=%20P%28z%3C0%29%20-%20P%28z%3C-1%29%20)
![=0.50-0.1587](https://tex.z-dn.net/?f=%20%3D0.50-0.1587%20)
or 34.13%
= 34% approximately
Therefore, the percent of data between 4.2 and 5.1 is about 34%
Answer:
2.4 liters
Step-by-step explanation: