Very complicated problem, but thank goodness I have too much time and am a nerd.
Basically model 1st account as so.
Fv=pv(1+I)^N
Fv future value
Pv present value
I interest
N number years
So first equation is interest earned after 3 years
Y=5000(1+0.023)^3
Y=5353 (rounded up)
So we know that the interest earned is 5353-5000 which is 353.
Now Ronisha (clearly the name of a future investment genius) invests these 353$ in a new account.
Now remember we’re not solving for FV we’re cause we’re given that: 55.2$
However this is the interest earned not the future value. So if interest earned is fv - pv and we know pv
Fv - 353 = 55.2
Fv = 408.2$
So now we reuse the formula
408.2 = 353(1+0.032)^x
Now just solve for x:
First divide both sides by 353
1.156 = 1.032^x
Remember the log rule that states x=b^y is same as y=logb(x)
So using the same logic:
X= log1.032(1.156)
Use some kind of calculator for that where you can adjust log base. But you basically get:
X= 4.602
So Ronisha has to basically invest 5 years or 4.6 years which is 4 years and 7 months.
Omg nevermind, wait it’s simple interest….
Sorry here’s the simple solution. My bad, but I worked so hard on the top part I don’t want to delete it.
I=prt
Interest = principal * rate * time
I= 5000(0.023)(3)=345
Then just do the same but plug 55.2 for I
55.2 = 345(0.032)t
Now solve for t
55.2 = 11.04t
t= 5
As you can see, similar logic where ultimately it takes 5 years. But this “genius” Ronisha should’ve just done compounding interest (my first calculation) and gotten it done in 4.6 years. Almost 5 months faster.
The interquartile range for these numbers is 22.5
Answer:
-2
Step-by-step explanation:
0.9x + 2.3x = -6.4
3.2x = -6.4
x = -2
For this question, all you have to do is subtract 6 from 10 to get 4. 4 + 6 is 10. z = 4.
Part 1: getting the area of the entrance
The entrance has a trapezoid shape.
Area of trapezoid can be calculated using the following rule:
Area of trapezoid = average base * height
The aveage base = (b1+b2)/2 = (8+16)/2 = 12 ft
height of trapezoid = 4 ft
Therefore:
area of entrance = 12*4 = 48 ft^2
Part 2: getting the area of the house:
area of house = area of back porch + area of side deck + area of play room + area of entrance
i- getting the area of the back porch:
The back porch is a square with side length = 6 ft
Therefore:
area of back porch = 6*6 = 36 ft^2
ii- getting the area of side deck:
The side deck is a rectangle whose length is 14 ft and width is 3 ft
Therefore:
area of side deck = 14*3 = 42 ft^2
iii- getting the area of play room:
The play room is a rectangle whose length is 14 ft and width is 16 ft
Therefore:
area of play room = 14*16 = 224 ft^2
iv- area of entrance is calculated in part 1 = 48 ft^2
Based on the above:
area of house = 36 + 42 + 224 + 48 = 350 ft^2
hope this helps :)