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Mathematics

1 answer:

scoray [572]2 years ago

3 0

8, 6

8^2=64
6^2=36

64+36=100

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2. The line that passes through the points (-6, p)

Kobotan [32]

Answer: -26=p

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Combining the xs gives us 6=(2-p)/-4.

Multiplying both sides by -4 leaves us with -24=2-p.

We do -24-2 to isolate p and find that p=-26.

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2 years ago

If a board measures LaTeX: 4\frac{3}{8}4 3 8 centimeters long and it is cut into lengths of LaTeX: 1\frac{2}{3}1 2 3 how many pi

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Answer:

Step-by-step explanation:

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2 years ago

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For the straight line defined by the points (4,57) and (6,91) , determine the slope ( m ) and y-intercept ( ???? ). Do not round

Ksivusya [100]

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2 years ago

Which number should go in the ?<br> 5 + 3 = 3 + 0<br> 5<br> 3<br> 8

soldi70 [24.7K]

Answer:

the answer is 5

Step-by-step explanation:

because 5+3 is 8 and 3+0 is 3 so you need 5 so it can be equal.

hoped i helped

5 0

3 years ago

Read 2 more answers

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago