Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = 
Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e
The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
Answer:
It's where they meet! I can't really see the coordinate clearly, but if I could I would tell you already.
Answer:
a)15:6 b)2:3
Step-by-step explanation:
No. of used books=15-9=6
a) 15:6
b)
6:9
2:3
To find a fraction between two fractions, all we need to do is make the sum of the numerators be the new numerator, and the sum of the denominators be the new denominator.(x) So, for example, a fraction between 7/13 and 6/11 is (7 + 6)/(13+ 11) =13/24.(x)
7/13 = .5384615(x)
6/11 = .545454(x)
13/24 = .541666�
Given that a/b < c/d, why is it true that a/b < (a+c)/(b+d)< c/d?
Since the triangle is a right triangle at point B, then line AB is perpendicular to line BC.
For perpendicular lines, the product of their slopes is -1.
Slope of AB = (5 - 0)/(2 - 5) = 5/-3 = -5/3
Slope of BC = (y - 5)/(7 - 2) = (y - 5)/5
-5/3(y - 5)/5 = -1
-5(y - 5)/15 = -1
-5(y - 5) = -15
y - 5 = 3
y = 3 + 5 = 8
Therefore, the y-coordinate of point C is 8.
