1) x³ + 2x² - x - 2 2) 2x³ + 5x² - 8x - 20 = 0
x²(x + 2) - (x + 2) x²(2x + 5) - 4(2x + 5) = 0
(x + 2)(x² - 1) (2x + 5)(x² - 4) = 0
(x + 2)(x - 1)(x + 1) x = -5/2, +-2
x = -2, 1, -1 << a is the answer.
hope that helps, God bless!
Answer:
f⁻¹(x) = 2x - 8
f⁻¹(4) = 2 × 4 - 8
f⁻¹(4) = 0
Step-by-step explanation:
Let's test it
So we do indeed have the inverse function, so using that we can plug in the values requested:
f⁻¹(x) = 2x - 8
f⁻¹(4) = 2 × 4 - 8
f⁻¹(4) = 0
Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
Answer:
(3x^2+21x+33) / (x+5)
You can use long division:
(3x^2+21x+33)
--------------------
(x+5)
=3x+6+ 3/x+5
Step-by-step explanation:
I’m not a true percent sure but I think it’s C