Answer:
9
Step-by-step explanation:
cross multiply 7/63 by 1/x
so, multiply 7 by x and 63 by 1
you get 63=7x
divide by 7 on both sides and you get 9
Answer:
1. z = 128
2. x = 4.2
3. c = 10
4. w = 100
5. a = 95.2
Step-by-step explanation:
1. Solve for z:
z/16 = 8
Multiply both sides of z/16 = 8 by 16:
(16 z)/16 = 16×8
(16 z)/16 = 16/16×z = z:
z = 16×8
16×8 = 128:
Answer: z = 128
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2. Solve for x:
3.5 x = 14.7
Divide both sides of 3.5 x = 14.7 by 3.5:
(3.5 x)/3.5 = 14.7/3.5
3.5/3.5 = 1:
x = 14.7/3.5
14.7/3.5 = 4.2:
Answer: x = 4.2
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3. Solve for c:
32 = 3.2 c
32 = 3.2 c is equivalent to 3.2 c = 32:
3.2 c = 32
Divide both sides of 3.2 c = 32 by 3.2:
(3.2 c)/3.2 = 32/3.2
3.2/3.2 = 1:
c = 32/3.2
32/3.2 = 10:
Answer: c = 10
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4. Solve for w:
(2 w)/5 = 40
Multiply both sides of (2 w)/5 = 40 by 5/2:
(5×2 w)/(2×5) = 5/2×40
5/2×2/5 = (5×2)/(2×5):
(5×2)/(2×5) w = 5/2×40
5/2×40 = (5×40)/2:
(5×2 w)/(2×5) = (5×40)/2
(5×2 w)/(2×5) = (2×5)/(2×5)×w = w:
w = (5×40)/2
2 | 2 | 0
| 4 | 0
- | 4 |
| | 0
| - | 0
| | 0:
w = 5×20
5×20 = 100:
Answer: w = 100
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5. Solve for a:
a/14 = 6.8
Multiply both sides of a/14 = 6.8 by 14:
(14 a)/14 = 14×6.8
(14 a)/14 = 14/14×a = a:
a = 14×6.8
14×6.8 = 95.2:
Answer: a = 95.2
Step-by-step explanation:
1st way: 5x
2nd way: 5.x
third way: 5(x)
equivalent fractions are fractions which have the same value.
equivalent fractions all have the same simplified form
we can write equivalent fractions by multiplying both numerator and denominator by the same number. We can also write equivalent fractions by dividing both numerator and denominator by the same number
so 5/10
we can get the equivalent fractions by multiplying by a common number
when we multiply by 2
when we multiply by 3
when we multiply by 4
the three equivalent fractions are
10/20 , 15/30, 20/40
Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
- Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams
- Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.
Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
- P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.
Next, multiply that by the sample size of 732.
- Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171
- For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
- P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.
- For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
