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hope this helps
Answer: Provided in the explanation section
Explanation:
The Question says;
Identify a logical operation (along
with a corresponding mask) that, when
applied to an input string of 8 bits,
produces an output string of all 0s if and
only if the input string is 10000001.
The Answer (Explanation):
XOR, exclusive OR only gives 1 when both the bits are different.
So, if we want to have all 0s, and the for input only 10000001, then we have only one operation which satisfies this condition - XOR 10000001. AND
with 00000000 would also give 0,
but it would give 0 with all the inputs, not just 10000001.
Cheers i hope this helped !!
Answer:
The method written in Java is as follows:
public static String reverseString(String str){
String result = "";
int lentt = str.length();
char[] strArray = str.toCharArray();
for (int i = lentt - 1; i >= 0; i--)
result+=strArray[i];
return result;
}
Explanation:
This defines the method
public static String reverseString(String str){
This initializes the result of the reversed string to an empty string
String result = "";
This calculates the length of the string
int lentt = str.length();
This converts the string to a char array
char[] strArray = str.toCharArray();
This iterates through the char array
for (int i = lentt - 1; i >= 0; i--)
This gets the reversed string
result+=strArray[i];
This returns the reversed string
return result;
}
<em>See attachment for full program that includes the main method</em>
