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2 years ago

Is there a log function that equals 17 urgent! pls dont give fake answers or ill report

Mathematics

1 answer:

xxTIMURxx [149]2 years ago

5 0

Answer: log(10^17) is 17.
Explanation: Honestly I just did trial and error until I got 17. This might not help.

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What is 423,090,709,000 in word form?

Kamila [148]

four hundred and twenty three billion, ninety million, seven hundred and nine thousand

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3 years ago

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There are 14 pieces of chalk and 42 packages of

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Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

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3 years ago

Please help with this problem. I keep getting -25

katrin [286]

$\bf -\sqrt[5]{-(400^2)}\implies -\sqrt[5]{-[(20\cdot 20)^2]}\implies -\sqrt[5]{-[(20^2)^2]}
\\\\\\
-\sqrt[5]{-(20^{2\cdot 2})}\implies -\sqrt[5]{-(20)^4}\implies -\sqrt[5]{-(2^2\cdot 5)^4}
\\\\\\
-\sqrt[5]{-2^{2\cdot 4}\cdot 5^4}\implies -\sqrt[5]{-2^8\cdot 5^4}\implies -\sqrt[5]{-2^{5+3}\cdot 5^4}
\\\\\\
-\sqrt[5]{-2^5\cdot 2^3\cdot 5^4}\implies 2\sqrt[5]{2^3\cdot 5^4}\implies 2\sqrt[5]{5000}$

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3 years ago

How many times are equal to 40000 pounds

Svetllana [295]

There are 20 us tons in 40,000 pounds.

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3 years ago

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