Considering that each input is related to only one output, the correct option regarding whether the relation is a function is:
A. yes.
<h3>When does a relation represent a function?</h3>
A relation represents a function when each value of the input is mapped to only one value of the output.
For this problem, we have that:
- The output is an activity.
There are no repeated inputs, hence the relation is a function and option A is correct.
More can be learned about relations and functions at brainly.com/question/12463448
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Answer:
0.5
Step-by-step explanation:
Ok, so it's asking for what (1/(x-1) - 2/(x^2-1)) approaches as x approaches 1. Before we deal with the limit, let's simplify the inside.
We want to combine the two fractions into one fraction. Therefore, we need a common denominator.
1/(x-1) is equal to (x+1)/((x+1)(x-1) is equal to (x+1)/(x^2-1).
the inside expression is therefore (x+1)/(x^2-1) - 2/(x^2-1)
which simplifies to (x-1)/(x^2-1).
and that simplifies further to 1/(x+1).
Now this is a continuous function when x = 1, so to find the limit as x approaches 1 of this function, we can by definition just plug 1 in.
limx->1 (1/(x+1)) = 1/2.
The reason why we didn't just plug 1 in at the beginning is because the function wasn't continuous when x was 1.
f(x) = 3x + 5/x
f(a + 2) = 3.(a + 2) + 5/(a + 2)
Alternative C.
(x - 2) • (x - 3) • (x - 4) • (x - 5)
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((((x4)-(14•(x3)))+71x2)-154x)+120
Step 2 :
Equation at the end of step 2 :
((((x4) - (2•7x3)) + 71x2) - 154x) + 120
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,4 ,5 ,6 ,8 ,10 ,12 ,15 , etc
